MATHEMATICS HIGH SCHOOL

Choose the correct graph of the given system of equations.y + 2x = −1
3y − x = 4

graph of two lines that intersect at the point (negative 1, 1)
graph of two lines that intersect at the point (1, 1) < Not
graph of two parallel lines with positive slopes
None of the above

Answers

Answer 1
Answer:

Answer: Graph of two lines that intersect at the point (negative 1, 1).

Step-by-step explanation:

The given system of linear equations :

y+2x=-1---------(1)\n\n3y-x=4-------------(2)

Multiply equation (1) by 3 , we get

3y+6x=-3-------------(3)

Subtract equation (2) from (3), we get

6x+x=-3-4\n\n 7x=-7

Divide both sides by 7 , we get

x=-1

Put value of x in (1), we get

y+2(-1)=-1\n\n y-2=-1\n\n y=-1+2=1

⇒ both lines are intersecting at (x,y)=(-1,1)

∴  The correct graph of the given system of equations : graph of two lines that intersect at the point (negative 1, 1)
Answer 2
Answer:

Answer:

(-1,1) One solution

Step-by-step explanation:

Use these steps for the equations:

1)  Rewrite the equation in slope intercept form.

2) Graph the first equation.

3) Graph the second equation.

4) Identify the point of intersection.

Related Questions

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-1/2x+3=-x+7 what does x equal
Please help. I’ll mark you brainliest. But no link andwers
Alicia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below:(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 7? 4 over 36 5 over 36 6 over 36 8 over 36
Subtract a^2 - 7a + 11 from the sum of 3a^2 - 4 and 5a^2 + 6a

Find an exact value cos(19pi/12)

Answers

cos\left ( (9\pi)/(12)\right )=\frac{\sqrt{2-√(3)}}{2}

Step-by-step explanation:

We know that

          cos 2x = 2cos²x - 1

So we have

          cosx=\sqrt{(1+cos2x)/(2)}

Substituting x=(19\pi)/(12)

         cos\left ( (19\pi)/(12)\right )=\sqrt{(1+cos2\left ( (19\pi)/(12)\right ))/(2)}\n\ncos\left ( (19\pi)/(12)\right )=\sqrt{(1+cos\left ( (19\pi)/(6)\right ))/(2)}\n\ncos\left ( (9\pi)/(12)\right )=\sqrt{(1+cos570)/(2)}\n\ncos\left ( (9\pi)/(12)\right )=\sqrt{(1-(√(3))/(2))/(2)}\n\ncos\left ( (9\pi)/(12)\right )=\sqrt{(2-√(3))/(4)}\n\ncos\left ( (9\pi)/(12)\right )=\frac{\sqrt{2-√(3)}}{2}

   cos\left ( (9\pi)/(12)\right )=\frac{\sqrt{2-√(3)}}{2}
19 π / 12 = 19 * 180° / 12 = 285 °
cos ( 19 π / 12 ) = cos 285° = cos ( - 75° ) = cos 75°
cos 75° = cos ( 45° + 30° ) = cos 45° cos 30° - sin 45° sin 30° =
= ( √2 / 2 · √3/2 ) - ( √2 / 2 · 1/2 ) = √6/4  - √2/4 =
= ( √6 - √2 )/ 4

Help with polynomials

Answers

(10x^2 + 5x + 3) + (2x^2 - 7x + 5) \n \n 10x^2 + 5x + 3 + 2x^2 - 7x + 5 \n \n (10x^2 + 2x^2) + (5x - 7x) + 3 + 5 \n \n 12x^2 - 2x + 3 + 5 \n \n 12x^2 - 2x + 8 \n \n

The answer is: 12x² - 2x + 8.
(10x^2+5x+3)+(2x^2-7x+5)
Add 10x^2 and 2x^2=12x^2
Subtract 7x from 5x=-2x
Add 3 and 5=8

Final Answer: 12x^2-2x+8

Hope this helps! :)

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