How to simplify 75/100

Answers

Answer 1

Answer: See what number go into both 75 and 100.
25 goes into both as 3*25 for 75
and 4*25 for 100
So to simplify it we take those two numbers and make another fraction
3/4

Answer 2

Answer: You can simplify it by dividing both numerator and denominator by 25 what will give us 3/4 (because 75 ÷ 25 = 3 and 100 ÷ 25 = 4).

I hope it will help you :)

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Answers

I want to say it is Skewed to the left because of more days with lower temperatures, but I could be wrong..

Answer:

Step-by-step explanation:

A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29 inches

Answers

For solving of the area of a square pyramid, we can use the formula below:
A=a²+2a sqrt (a²/4 +h²)
where s for the slant height, r for the a/2, where a is the side length and h for the height
Substitute the values,
A=40²+(2*40) SQRT (40²/4 +21²)
A=3920
The answer is 3920 for the area of the square pyramid.

Answer with explanation:

Base of Pyramid which is in the shape of square ,having length of each side =40 inches

Height of pyramid = 21 inches

Slant height = 29 inches

Surface area of Square Pyramid

= Area of four Triangular faces +Area of Square base

Relation between Slant height (S), Length of base (B) and Height (H) of pyramid

$S=(√(B^2+4H^2))/(2)$

$29^2=\sqrt{(40^2)/(4)+21^2}$

So,this is a Square pyramid.

Surface area of Pyramid

$=B*(B+2 S)\n\n=B *(B+√(B^2+4H^2))\n\n=40 *(40+√(40^2+4* 21^2))\n\n=40 *(40+√(3364))\n\n=40 *(40+58)\n\n=40 * 98\n\n=3920$ square inches

Volume of Pyramid

$=(1* a^2* H)/(3)\n\n=(40^2 * 21)/(3)\n\n=1600 * 7\n\n=11200$ cubic inches

What would be m minus 4 in an algebraic expression

Answers

It's just m minus 4
m - 4

Simplify (2n + 5) - (3n + 7) + (4n - 9).
-3n - 11
3n - 11
-3n + 11
3n + 11

Answers

☸ We are going to simplify this Step-By-Step. ☸

☸ First here is the question you ask:

2n+5−(3n+7)+4n−9

☸ Lets start with this:

=2n+5+−3n+−7+4n+−9

☸ Now lets Combine Like Terms:
(Pst the bold stuff is for Combining Like Terms)

=2n+5+−3n+−7+4n+−9

=(2n+−3n+4n)+(5+−7+−9)

☸ Your answer shall be:

=3n+−11

☸Hope this helps!☸

Los datos siguientes corresponden a los tiempos de reacción de una muestra de 33 sujetos, medidos en centésimas de segundo(Inventar los dos últimos datos, reemplazando las x por un número): 55, 51, 60, 56, 64, 56, 63, 63, 61, 57, 62, 50, 49, 70, 72, 54, 48, 53, 58, 66, 68, 45, 74, 65, 58, 61, 62, 59, 64, 57, 63, xx, xx. 1. Calcular los cuartiles de los 33 sujetos 2. Calcular el decil 5 y el decil 7 3. Calcular el percentil 13 y el percentil 76

Answers

Responder:

Compruebe amablemente la explicación

Explicación paso a paso:

Dados los datos: 55, 51, 60, 56, 64, 56, 63, 63, 61, 57, 62, 50, 49, 70, 72, 54, 48, 53, 58, 66, 68, 45, 74, 65, 58, 61, 62, 59, 64, 57, 63, xx, xx

Los dos valores faltantes podrían ingresarse utilizando varios métodos, incluyendo la mediana, modal y el valor medio de los datos dados en la distribución.

Aquí usaremos el valor medio.

Media (m) de los datos = suma de la observación / número de observaciones Media =

(55 + 51 + 60 + 56 + 64 + 56 + 63 + 63 + 61 + 57 + 62 + 50 + 49 + 70 + 72 + 54 + 48 + 53 + 58 + 66 + 68 + 45 + 74 + 65 + 58 + 61 + 62 + 59 + 64 + 57 + 63) / 31 = 1844/31 = 59.4 = 59 (al número entero más cercano) Entonces reemplace los valores faltantes con 59.

En otro para hacer cálculos sobre los datos, hay que reorganizarlos.

Datos ordenados: 45,48,49,50,51,53,54,55,56,56,57,57,58,58,59,59,59,60,61,61,62,62,63,63,63, 64,64,65,66,68,70,72,74

Los cuartiles de datos:

Primer cuartil (Q1) = 1/4 (33 + 1) = 1/4 (34) = 8.5

Q1 = (8º + 9º) / 2 = (55 + 56) = 111/2 = 55,5

Segundo cuartil (Q2) = Q3 - Q1 = (25.5 - 8.5) = 17th = 59

Tercer cuartil (Q3) = 3/4 (33 + 1) = 3/4 (34) = 25.5 Q3 = (25 + 26) = (63 + 64) = 127/2 = 63.5

Rango intercuartil (IQR) = 63.5 - 55.5 = 8

Mediana = Q2 = 59

Mínimo = 45

Máximo = 74

Rango = 74-45 = 29

El quinto decil:

D5 = [5 (33 +1)] / 10 = 5 (34) / 10

D5 = 170/10 = 17º valor = 59

7mo decil: D7 = [7 (33 + 1)] / 10 = 7 (34) / 10

D7 = 238/10 = 23.8 ° término D7 = 63

Percentil:

Percentil 13 (13% × 33) = 0.13 × 33 = 4.29

4to término = 50

Percentil 76: (76% × 33) = 0.76 × 33 = 25.08

25 ° término = 63

Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. When he starts his shift, the water level shows 4 gallons, or 128 cups of water. As the shift progresses, he records the level of the water every 10 minutes. After 2 hours, he uses a regression calculator to compute an equation for the decrease in water. His equation is W –0.414t + 129.549, where t is the number of minutes and W is the level of water. According to the equation, after about how many minutes would the water level be less than or equal to 64 cups

Answers

The correct answer is:

t ≥ 158.33, or rounded, t ≥ 160.

Explanation:

The equation we're given is
W = -0.414t + 129.549, which an be written as
-0.414t + 129.549 = W.

We are asked to find the amount of time it would take for the water level to be less than or equal to 64 cups. Plugging this information in, we have:

-0.414t + 129.549 ≤ 64

To solve this, we first cancel 129.549 by subtracting from both sides:
-0.414t + 129.549 - 129.549 ≤ 64 - 129.549
-0.414t ≤ -65.549

Now divide both sides by -0.414:
-0.414t/-0.414 ≤ -65.549/-0.414
t ≥ 158.33

(When we multiply or divide both sides of an inequality by a negative number, we must flip the inequality symbol.)

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