Step-by-step explanation:
You have given a point (1, -5), a slope of 5, and the line passes through the point (-1, -3). You can use this information to find the equation of the line.
The equation of a line in point-slope form is:
y - y1 = m(x - x1)
Where (x1, y1) is a point on the line, and m is the slope.
Using the given point (1, -5) and the slope m = 5, you can plug these values into the equation:
y - (-5) = 5(x - 1)
Now, simplify:
y + 5 = 5(x - 1)
To put it in slope-intercept form (y = mx + b), expand and solve for y:
y + 5 = 5x - 5
Subtract 5 from both sides:
y = 5x - 5 - 5
y = 5x - 10
So, the equation of the line with a slope of 5 that passes through the point (1, -5) is:
y = 5x - 10
28
34
49
21
54
63
Y= 1/2x + 1
Plot all ordered pairs for the values in the domain.
D: { -8,-4,0,2,6}
A graph of the linear function y = 1/2(x) + 1 is shown in the image attached below.
In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;
y = mx + b
Where:
Since the given linear function y = 1/2(x) + 1 is in slope-intercept form, we would start by plotting the y-intercept:
y = 1/2(x) + 1
y = 1/2(0) + 1
y = 1 ⇒ (0, 1)
y = 1/2(-8) + 1
y = 1 ⇒ (-8, -3)
y = 1/2(-4) + 1
y = 1 ⇒ (-4, -1)
y = 1/2(2) + 1
y = 1 ⇒ (2, 2)
y = 1/2(6) + 1
y = 1 ⇒ (6, 4)
Next, we would use an online graphing tool to plot the given linear function for the values in its domain { -8,-4,0,2,6} using table, as shown in the graph attached below.
Read more on a graph here: brainly.com/question/4546414
#SPJ3
To plot the ordered pairs for the given domain of a linear function, substitute each value of x into the equation and solve for y.
To plot the ordered pairs for the values in the given domain, we substitute each value of x into the equation and solve for y. Let's do that for each value in the domain:
The ordered pairs for the given domain are (-8, -3), (-4, -1), (0, 1), (2, 2), and (6, 4).
#SPJ12
Answer:
(- 1, 4 )
Step-by-step explanation:
x = 1 is a vertical line passing through all points with an x- coordinate of 1
The point P(3, 4) is to units to the right of x = 1.
Hence the refection will be 2 units to the left of x = 1
P' = (1 - 2, 4 ) = (- 1, 4 )
–50xy
–40x2
24
10y
Answer:
–50xy
–40x2
Will not change the Greatest Common Factor.
Step-by-step explanation:
Greatest common factor is the highest factor that divides 2 or more number.
We can find the GCF by multiplying all the factors that are common to each number.
Factors of =1,2,3,4,6,9,12,18, 36 and ,,,
Factors of =1,2,11, and
Factors of =1,2,3,4,6,8,9,12,16,18,24,36 and and more.
So the common factors to all three numbers are 1,2 and x.
So GCF =
If we use 11 it will change the GCF to 11.
If we use it will not change the GCF.
If we use 40 it will not change the GCF.
IF we use 24 it will change the GCF.
If we use 10y it will change the GCF.
x^2 + 3x - 28/ x^2 - 7x + 12
Show your work.
Answer:
(x^4 + -4 x^3 + 12 x^2 - 28)/x^2
Step-by-step explanation:
Simplify the following:
x^2 + 3 x - 7 x + 12 - 28/x^2
Put each term in x^2 + 3 x - 7 x + 12 - 28/x^2 over the common denominator x^2: x^2 + 3 x - 7 x + 12 - 28/x^2 = x^4/x^2 + (3 x^3)/x^2 - (7 x^3)/x^2 + (12 x^2)/x^2 - 28/x^2:
x^4/x^2 + (3 x^3)/x^2 - (7 x^3)/x^2 + (12 x^2)/x^2 - 28/x^2
x^4/x^2 + (3 x^3)/x^2 - (7 x^3)/x^2 + (12 x^2)/x^2 - 28/x^2 = (x^4 + 3 x^3 - 7 x^3 + 12 x^2 - 28)/x^2:
(x^4 + 3 x^3 - 7 x^3 + 12 x^2 - 28)/x^2
Grouping like terms, x^4 + 3 x^3 - 7 x^3 + 12 x^2 - 28 = x^4 + (3 x^3 - 7 x^3) + 12 x^2 - 28:
(x^4 + (3 x^3 - 7 x^3) + 12 x^2 - 28)/x^2
3 x^3 - 7 x^3 = -4 x^3:
Answer: (x^4 + -4 x^3 + 12 x^2 - 28)/x^2