A a0 is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade.

Answers

Answer 1

Answer: The correct answer that would best complete the given statement above would be the term KILOCALORIE. A KILOCALORIE is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade. On the other hand, the amount of heat needed to raise the temperature of one gram of water one Centigrade degree is calorie. Hope this answer helps.

Answer 2

Answer:

I got this correct on Odyssey-ware the answer is Kilocalorie

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Intro physics course is beginning to move into 2D kinematics, stuck on the first real question.A stone is thrown horizontally at 15m/s from the top of a cliff 44m high. What is the velocity of the rock after 2 seconds?
I tried 3(-9.8m/s2) and some other formula's but could never arrive at the correct answer of 24.7m/s. Could someone explain how to arrive at this answer and the reasoning behind it?

Answers

-- You kick it horizontally, out off of the cliff, at 15 m/s. There's no horizontal
force on it, so its horizontal speed never changes.

-- As soon as it clears the edge of the cliff, gravity starts accelerating it
downward, 9.8 m/s faster every second. After 2 seconds, it has

   (2 x 9.8) = 19.6 m/s

of downward vertical speed.

At this point, its velocity points somewhere between horizontal and downward-
vertical. I gather from the wording of the question that you're not so much
concerned with the direction of the velocity as you are with its magnitude ...
that is, the stone's speed in whatever direction it's actually moving.

You have a vector with two components: 15 horizontal and 19.6 vertical.
Those components are perpendicular, so their resultant is just the hypotenuse
of the right triangle.

   (Speed)² = (15 m/s)² + (19.6 m/s)²

   = (225 m²/s²) + (384.16 m²/s²)

   = (609.16 m²/s²) .

   Speed = √(609.16 m²/s²) = 24.681 m/s

That's where the 24.7 m/s comes from. /\

(I just looked back at the question again. Notice that we don't care
how high the cliff is. That "44m" is in there only to distract those who
don't know what they're doing, and who think that they must use it
just because it's there.)

ok so the x velocity is 15 m/s with no acceleration
the y velocity is 19.62 after 2 seconds because of acceleration of 9.81 m/s x 2

the velocity can be found by making a diagram and solving through the pythagorean theorem

15 sq + 19.62 sq = velocity sq
225 + 384.9444 = velocity sq
velocity = sqrt 609.944
velocity = 24.7

What is the French word for shepherds crook

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The answer would be:

Houlette de berger.

"shepherd's crook" means "houlette de berger" in french

Restate newton's third law of motion

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Newton's third law states that, for every action there is an equal and opposite reaction.

Mathematically, Fa = -Fr

Hope this helps!

reflecting, spherical Christmas tree ornament has a diameter of 9.0 cm. A child looks at the ornament from a distance of 12 cm. Describe the image she sees.

Answers

The distance of the image observed by th girl is 2.77 cm.

Focal length of the lens

The focal length of the lens is calculated as follows;

F = R/2

where;

R is the radius of lens

R = 9 cm/2 = 4.5 cm

F = R/2

F = 4.5/2

F = 2.25 cm

Image distance

The distance of the image observed by th girl is caculated as follows;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/2.25 - 1/12

1/v = 0.3611

v = 2.77 cm

Thus, the distance of the image observed by th girl is 2.77 cm.

Learn more about image formed by lens here: brainly.com/question/6722295

f = R/2

(9/2)/2 = 2.25 cm

i = 1/(1/f - 1/o)

1/(1/2.25 - 1/12) = 1/2.769 ⇒ 0.36

I believe the image would appear upright.

A planet has a mass of 5.68 x 1026 kg and a radius of 6.03 x 107 m. What is the weight of a 65.0 kg person on the surface of this planet?

Answers

Weight is dependent on both the mass of the object and the gravitational pull of a planet. This is why people weigh differently on other planets, which have a different gravitational force. Using the formula W = G(m1)(m2)/r^2 where:

W = weight or force
G = Gravitational constant (not the same as g) = 6.67x10^-11 m^2/kg^2
m1 = mass of object 1 (person)
m2 = mass of object 2 (planet)
r = radius of planet

This gives a weight of 677.26 Newtons

What is the temperature change when 69.0kJ is transferred to a 1.20kg object with a specific heat capacity of 250J/(kg ∘ C)?