Given DA = 14, A F = 21, KE = x, and EF = 15. What must the value of x be in order to prove AE || KD?
Answers
Using cross multiplication you can determine that the ANSWER is 10.
Answer:
Step-by-step explanation:
We have been given an image of a triangle. We are asked to find the value of x.
We can see that triangle AFE is similar to triangle DFK. We know that corresponding sides of similar triangle are proportional, so we can set an equation to solve for x as:
Upon cross multiplying our given equation, we will get,
Therefore, the value of x is 10.
Related Questions
Which product is positive?
Product of 6 and 6r and the product of 8s and 4
Find the product (-2)(3)
lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.
(B) Find the demand equation.
(C) Find the equilibrium price and quantity
Answers
Answer:
(A) Find the supply equation.
Qs = 245.67 + 333.33Ps
(B) Find the demand equation.
Qd = 1079 - 1000Pd
(C) Find the equilibrium price and quantity
Price P = $0.625
Quantity Q = 454 bushels
Step-by-step explanation:
The demand equation is of the form;
Q = a - bP
The supply equation is of the form;
Q = c + eP
We need to determine the values of a,b,c,d;
At $ 0.49 per bushel, the daily supply for wheat is 409 bushels, and the daily demand is 589 bushels
589 = a - b(0.49) ........1
409 = c + e(0.49) .........2
When the price is raised to $ 0.85 per bushel, the daily supply increases to 529 bushels, and the daily demand decreases to 229 bushels;
229 = a - b(0.85) ........3
529 = c + e(0.85). .......4
Subtract equation 3 from 1
589-229 = b(0.85) - b(0.49)
360 = b(0.36)
b = 360÷0.36
b = 1000
Using equation 1
589 = a - 1000(0.49)
a = 589+490 = 1079
Subtract equation 2 from 4
529-409= e(0.85) - e(0.49)
120 = 0.36e
e = 120/0.36
e = 333.33
Using equation 2
409 = c + 333.33(0.49)
c = 409 - 333.33(0.49)
c = 245.67
Therefore the demand equation is;
Qd = 1079 - 1000Pd
The supply equation is ;
Qs = 245.67 + 333.33Ps
The equilibrium price is at Qs = Qd and Ps = Pd
1079-1000P = 245.67 +333.33P
P = (1079-245.67)/(1000+333.33)
P = $0.625
Qd = 1079 - 1000(0.625)
Qs = Qd = 454
Answers
Answer:
b
Step-by-step explanation:
b. 6.9 units
c. 9.2 units
d. 5 units
need an explanation if possible please.
Answers
Answer:
6.08units
Step-by-step explanation:
The distance between two points of a line is expressed as;
D = √(y2-y1)²+(x2-x1)²
Given the coordinates (3, -5) and (4, 1);
D = √(1+5)²+(4-3)²
D = √(6)²+(1)²
D = √36+1
D = √37
D = 6.08 units
Hence its length is 6.08units
B. Approximately 255,000 miles per day
C. Approximately 501,000 miles per day
D. None of these
Answers
The approximate circumference of the orbit is 93 x 2 x PI = 584.34 billion miles.
Divide that by the number of days:
584.34 / 365.25 = 1.6 million miles a day
The options are
-Is
-Is not
Answers
Answer:
the rate of change is constant
Step-by-step explanation:
b. you add 6000 kilograms of water to the pool. what is the depth of the water in the pool? write your answer as a fraction. the water is about meters deep.
Answers
Answer:
1). Mass of water present= 18000 kg
2).4/3 meters deep
Step-by-step explanation:
Area of the rectangle= 6*3= 18m²
Volume of water in the pool
= Deepness of water*area of rectangle
= 1*18
= 18 m³
density of water is about 1 gram per cubic centimeter
In kg per m³= 1000 kg/me
Mass of water present= density*volume
Mass of water present= 1000*18
Mass of water present= 18000 kg
2)6000 kilograms of water is added to 18000 of
Total mass present= 6000+18000
Total mass present=24000 kg
If density= 1000kg/m³
Volume present= mass/density
Volume present= 24000/1000
Volume present= 24 m³
Area of the rectangle= 18 m²
deepness of the pool= volume/area
deepness of the pool= 24/18
deepness of the pool= 4/3 meters deep