Did i do this correctly?​
did i do this correctly?​ - 1

Answers

Answer 1
Answer:

Answer:

R" has coordinates (-4,6)

Explanation:

The pre-image is the original, while the image is the altered form. The image is notated by a '. When you alter the image ('), you get ".

T is dilated (multiplied) by 5, so it goes from T = (1,-2) to T' = (5, -10)

R = (-2, 3) → (multiply by 5) → R' = (-10, 15) → (multiply by 2/5 or 0.4) → R" = (-4, 6)


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(2x - y + 3) (2x - y - 3)using identities ​

Answers

Step-by-step explanation:

(2x-y+3)(2x-y-3)=

4x²-2xy-6x-2xy+y²+3y+6x-3y-9=

4x²-4xy+y²-9=

(2x-y)²-9

Which expressions represent rational numbers? Check all that apply.

Answers

The answers are numbers two and four.

Answer:

Step-by-step explanation:

NVM ITS WRONG

What is the difference between 2:45am and 12:32pm

Answers

pm is afternoon, am is in the morning

post meridiem is pm an which translates from Latin to after noon, A.m. “ante meridiem” is Latin for “before noon” or “midday”
Hope this helps!!

Please Help!!In 2010, Martin paid $5,518.00 in Social Security tax. The SS tax rate was 6.2%. What was Martin's taxable income in 2010?

Answers

Answer:

$890 or it's $34211.6

Step-by-step explanation:

you divide 5518 by 6.2% or you multiply them

Ava's cat is 3 pounds heavier than her puppy. if their combined weight is 27 pounds, how much does her cat weight

Answers

Answer:

12

Step-by-step explanation:

(3+x)+x=27

2x+3=27

2x=24

x=12

her cat weighs 16.5 pounds i think

A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an average of 18 games, with a population standard deviation of 6 games. If a sample of only 2 friends is selected at random from the group, select the expected mean and the standard deviation of the sampling distribution from the options below. Remember to round to the nearest whole number.

Answers

Answer: \mu_x=18\text{ hours}

\sigma_x=4\text{ hours}

Step-by-step explanation:

We know that mean and standard deviation of sampling distribution is given by :-

\mu_x=\mu

\sigma_x=(\sigma)/(√(n))

, where \mu = population mean

\sigma =Population standard deviation.

n= sample size .

In the given situation, we have

\mu=18\text{ hours}

\sigma=6\text{ hours}

n= 2

Then, the expected mean and the standard deviation of the sampling distribution will be :_

\mu_x=\mu=18\text{ hours}

\sigma_x=(\sigma)/(√(n))=(6)/(√(2))=4.24264068712\approx4  [Rounded to the nearest whole number]

Hence, the the expected mean and the standard deviation of the sampling distribution :

\mu_x=18\text{ hours}

\sigma_x=4\text{ hours}