Brian has $88 and he saves $3.50 a week how many more weeks will it take him to get to 200​

Answers

Answer 1
Answer:

Answer:

32 weeks

Step-by-step explanation:

First you should write an equation for this word problem. Since you know Brian wants to save to $200, the equation will equal 200. Then you figure out how much he has already, which is 88. Right now, the equation we have is 88+(weekly savings)= 200. He saves 3.50 a week, so the equation will finally look like 88+3.50x=200. X is how many weeks it will take for him to reach 200. We then move everything so that it all equals X. You would move the 88 first which will then give 3.50x=112. Dividing by 3.50 on both sides would give X as 32. SO the number of weeks it will take for Brian to save to $200 is 32 weeks.


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HELP PLEASE!!! The following graph shows farm sector production in billions of dollars from 1994–2003. One line shows the yearly production and the other shows the average over the time span. According to the graph, in which 3 years were the values of farm sector production closest to the average for the 10 years shown?

A): 1994, 1996, 1998
B): 1996, 1998, 2000
C): 1998, 2000, 2002
D): 2000, 2002, 2004

Answers

Answer:

C): 1998, 2000, 2002

Explanation:

You can find the answer by looking at which part of the line graph intersects the line where it says 1994-2003 average. As you can see, the years 1998, 2000, and 2002 are meeting up with the average of 1994-2003.

Answer: C) 1998, 2000, 2002 !!

Step-by-step explanation:

You have a triangle that has side lengths of 6,9,and 12. Give the side lengths of a similar triangle that is smaller than the given triangle.

Answers

Those lengths have a common factor of 3. Removing that factor gives you the smaller similar triangle with sides 2, 3, and 4.

Ten measurements of impact energy on specimens of A238 steel at 60 ºC are as follows: 64.1, 64.7, 64.5, 64.6, 64.5, 64.3, 64.6, 64.8, 64.2, and 64.3 J. a. Use the Student’s t distribution to find a 95% confidence interval for the impact energy of A238 steel at 60 ºC. b. Use the Student’s t distribution to find a 98% confidence interval for the impact energy of A238 steel at 60 ºC.

Answers

Answer:At 95% confidence interval, the lower end is 64.306 and the upper end is 64.614

At 98% confidence interval, the lower end is 64.268 and the upper end is 64.652

Step-by-step explanation:

PLEASE HELP!
DUE SOON STEP BY STEP PLEASE PLEASE HELP ASAP

Answers

Answer:

Step-by-step explanation:

yep your correct :)

A plant produces 500 units/hour of an item with dimensions of 4” x 6” x 2”. The manager wants to store two weeks of supply in containers that measure 3 ft x 4 ft x 2 ft. (Note: She can store the units in the containers such as that the 4” dimension aligns with either the 3 ft width or the 4 ft length of the box, whichever allows more units to be stored.) A minimum of 2 inches of space is required between adjacent units in each direction. If the containers must be stacked 4-high, and the warehouse ceiling is 9 feet above the floor, then determine the amount of floor space required just for storage.

Answers

Answer:

  564 ft²

Step-by-step explanation:

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

  3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

  (4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

  47 × 12 ft² = 564 ft²

of warehouse floor space required for storage.

_____

The second attachment shows the top view and side view of units packed in a storage box.

Will mark as brainliest if correct! (#14)

Answers

Answer:

B and D

Step-by-step explanation:

To find the percentage, you divide Martin's correct answers by the total number of questions, then multiply the result by 100.

To find the fraction, it's correct answers/total questions.

Answer:

you should get your answer to be ,B and D