Answer:
s^3 + 12
Step-by-step explanation:
To get the missing volume you need to do:
height x length x width or s^3.
Then, add that volume to the existing 12 volume:
s^3 + 12.
Hopefully this helped!
Brainliest please?
Answer: I don't know do it your self
Step-by-step explanation:
Answer:
C) not justified, since people usually swim in the ocean during the day.
Answer:
Greater number: 77 Lesser number: 20
Step-by-step explanation:
Sooo
20 × 4 is 80
80 - 3 = 77
77 + 20 = 97
Answer:
77 & 20
Step-by-step explanation:
x+y=97
x=4y-3
4y-3+y=97
5y=97+3
5y=100
5 5
y=20
x=4y-3
x=4(20)-3
x=80-3
x=77
don't forget to follow , rate & like
How many times is the volume of the large sphere than the
small sphere?
2
VX
O 4
O 6
O 8
Answer:
4 times as great
Step-by-step explanation:
Compute the two different volumes and then compare them.
Smaller sphere: V = (4/3) · π ·r²
Larger sphere: V = (4/3) · π · (2r)² = (4/3) · π · 4 · r²
Comparing these, one sees immediately that the volume of the larger sphere is 4 times as great as that of the smaller sphere.
Answer:
24 million
Step-by-step explanation:
24,000,000 if you put it porperly
The units are, Unit, Tens, Hundreds, Thousand, Ten-Thousand, Hundred-Thousand, Million, Ten million, Hundred million Billion and so on
Answer:
1000/t=w
Step-by-step explanation:
The first thing we need to do is, multiply 1000 to both sides,
c(1000)=wtc
now we need to divide both sides by tc
c(1000))/(tc)=w
The c's on the left side will cancel out
1000/t=w
Step-by-step explanation:
hdhdhdhdhddjdifififiifr
Answer:
V= 22-2t
Step-by-step explanation:
I guess the alphabet should be v instead of y. So I am working using v
The rate at which water is draining from the tank is 2gallons/hour. This is the rate of water removal from the tank. So after an hour, 2 × 1= 2 gallons would have drained. After 5 hours, 2×5 =10 gallons would have drained
Therefore to obtain the amount of water in gallons that have been removed from the tank, you will multiply the rate by the time in hours after which the draining started.
Amount (gallons) =2×t
The amount of water remaining in the tank will be obtained by subtracting the amount of water drained after some hour (2×t) from the initial amount of water in the tank (22)
Therefore, the amount of water present in the tank (v)= 22-2t or 2(11-t) gallons
The formula to express volume of the water v in terms of time t is v = 22 - 2t, where 22 is the initial volume and 2t represents the rate at which the water is draining.
This problem is a mathematical representation of a real-world scenario using a linear equation. The volume of water v in the tank can be represented in terms of time t through the equation v = 22 - 2t. This equation illustrates the initial volume of water in the tank (22 gallons) and accounts for the constant rate at which the water is draining (2 gallons per hour).
When time t = 0 (meaning no time has passed since the water started draining), the volume of water v = 22 (the initial volume). As time increases, the volume gradually decreases at a rate of 2 gallons per hour, represented by the term -2t.
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