A car company claims that its cars achieve an average gas mileage of at least 26 miles per gallon. A random sample of five cars form this company have an average gas mileage of 25.2 miles per gallon and a standard deviation of 1 mile per gallon. At α=0.06, can the company’s claim be supported, assuming this is a normally distributed data set?
Answers
Answer with explanation:
Let be the population mean.
Null hypothesis :
Alternative hypothesis :
Since the alternative hypothesis is left tailed, so the test is a left-tailed test.
Sample size : n=5 <30 , so we use t-test.
Test statistic:
Critical t-value for t=
Since, the absolute value of t (1.79) is less than the critical t-value , so we fail to reject the null hypothesis.
Hence, we have sufficient evidence to support the company's claim.
Related Questions
3 3/4 divided by 5/7
What is the greatest common factor of 12 and 90?
Kyle wants to buy a new laptop that has an original price of $540. The store is having a sale, so the laptop is 10 percent off, which amounts to a discount of $54. If sales tax is 8 percent on the final price of the laptop, how much tax will he need to pay?
Please helpdetermine all the unknown values of the figure below.
Answers
Answer:
24 minutes
Step-by-step explanation:
Distance = speed x time
12 mi = 30 mi/h x time
time = 12/30 = 4/10 hours
since 1 hour has 60 minutes
4/10 hours x 60 = 24 minutes
Answer:
It will take her 24 minutes to get there.
Hope This Helps! :) Plz Give Brainliest!
Answers
Answer:
Step-by-step explanation:
Qp = charge on proton = 1.6 x 10-19 C
Qs = charge on silicon = 14 x 1.6 x 10-19 C
rf = final distance from nucleus = ∞
ri = initial distance from nucleus = (3.6 x 10-15 + 1.2 x 10-15 ) = 4.8 x 10-15 m
initial Potential energy is given as
Ui = k Qp Qs / ri = (9 x 109) (1.6 x 10-19 ) (14 x 1.6 x 10-19 ) / (4.8 x 10-15 ) = 6.72 x 10-13 J
final Potential energy is given as
Uf = k Qp Qs / rf = (9 x 109) (1.6 x 10-19 ) (14 x 1.6 x 10-19 ) / (∞) = 0 J
Change in Potential energy = ΔU = Ui - Uf = 6.72 x 10-13 - 0 = 6.72 x 10-13 J
Let the Voltage through which proton is accelerated = V
Energy gained due to potential difference = Qp V
Using conservation of energy
Qp V = 6.72 x 10-13
(1.6 x 10-19 ) V = 6.72 x 10-13
V = 4.2 x 106 volts
a. 608/23
=____\_____
=_____
Answers
Answer:
Step-by-step explanation:
26.43
(26)
Answers
Making a proportion helps solve this problem. Cm on top, km on bottom.
1 9
---- = ----
20 ?
Cross multiply to get 1? = 180
? = 180.
The distance is 180 km.
Final answer:
The conversion of 9 cm on the map to an actual distance, using the given scale of 1 cm for 20 km, results in an actual distance of 180 kilometers.
Explanation:
The question is asking for the actual distance corresponding to 9 cm on the map. According to the given scale on the map, 1 cm corresponds to an actual distance of 20 km. So to find out how many kilometers 9 cm on the map would be in real life, we simply multiply the length measured on the map by the distance each centimeter represents. This gives us:
9 cm * 20 km/cm = 180 km
So, according to the map, 9 cm corresponds to an actual distance of 180 kilometers.
Learn more about Map Scale Conversion here:
#SPJ3
Multiples of 15: 15, 30, 45, 60, . . .
The least common multiple is 60.
What is Maria’s error?
the answer is IDK
Answers
Answer:
The Least Common Multiple is 3
Step-by-step explanation:
Maria's error was that she tried finding the largest multiple rather than the least.
Answer:
Step-by-step explanation:
Maria's error on this is the LCM is 30 not 60
the least is 30 not 60
Answers
Answer:
Part A: -8
Part B: -4
Step-by-step explanation: