Suppose that the maximum weight that a certain type of rectangular beam can support varies inversely as it’s length and jointly as its width and the square of its height. Suppose also that a beam 5 inches wide, 2 inches high and 10 feet long can support a maximum weight of 8 tons. What is the maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

Answers

Answer 1

Answer:

4 tons is maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

What is Weight?

Gravitational force of attraction on an object, caused by the presence of a massive second object, such as the Earth or Moon.

Given,

Maximum weight that a certain type of rectangular beam can support varies inversely as it’s length and jointly as its width and the square of its height.

beam 5 inches wide, 2 inches high and 10 feet long can support a maximum weight of 8 tons.

W = k × w × h²/ L

8 = k × 5 × 2² / 10

8 = k ×20/10

8 = 2 × k

k = 4

The maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

w =4 ×6 ×2² / 24

= 24 ×4/ 24

W=4 tons

Hence 4 tons is maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long

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Answer 2

Answer:

Way: W = k * w * h^2/ L

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Please help me on this

Answers

For this case, we have that by definition:

$(-0.5) ^ 3 = -0.125$

Then we can rewrite the given expression as:

$\sqrt [3] {(- 0.5) ^ 3}$

For properties of roots we have that:

$\sqrt [n] {(a) ^ n} = a$

So:

$\sqrt [3] {(- 0.5) ^ 3} = - 0.5$

So, we have to:

$\sqrt [3] {- 0.125} = - 0.5$

ANswer:

Option A

Simplify the radical by breaking the radicand up into a product of known factors.
Your answer is A. -0.5

It took Fred 12 hours to travel over pack ice from one town to another town 360 miles away. During the return journey it took him 15 minutes

Answers

Step-by-step explanation:

what is your question please

If quadrilateral PQRS is an isoceles trapezoid if RP=12 then SQ= ?

Answers

The question is missing parts. Here is the complete question.

Quadrilateral PQRS (shown below) is an isosceles trapezoid. If RP = 12, then SQ = ?

Answer: SQ = 12

Step-by-step explanation: A trapezoid is a quadrilateral with two opposite parallel sides, called bases. The trapezoid is an isosceles trapezoid when the non-parallel sides have the same length.

One property of isosceles trapezoid is that its diagonals are congruent, i.e., have the same length.

In the picture, segment RP is one of the trapezoid's diagonal. It is asking the measure of SQ, which is the other diagonal. So:

SQ = RP

SQ = 12

Segment SQ of isosceles trapezoid PQRS is 12 units.

Answer:

if quadrilateral PQRS is an isosceles trapezoid if RP=12 then SQ= 12

Step-by-step explanation:

A fair die is rolled 8 times. What is the probability that the die comes up 6 exactly twice? What is the probability that the die comes up an odd number exactly five times? Find the mean number of times a 6 comes up. Find the mean number of times an odd number comes up. Find the standard deviation of the number of times a 6 comes up. Find the standard deviation of the number of times an odd number comes up.

Answers

Answer:

0.2605, 0.2188, 1.33, 4, 1.0540, 1.4142

Step-by-step explanation:

A fair die is rolled 8 times.

a. What is the probability that the die comes up 6 exactly twice?

b. What is the probability that the die comes up an odd number exactly five times?

c. Find the mean number of times a 6 comes up.

d. Find the mean number of times an odd number comes up.

e. Find the standard deviation of the number of times a 6 comes up.

f. Find the standard deviation of the number of times an odd number comes up.

a. A die is rolled 8 times. If A represent the number of times a 6 comes up. For a fair die the probability that the die comes up 6 is 1/6 - Thus A ~ Bin(8, 1/6)

The probability mass function of the random variable A is

$p(A) = \left \{ {(8!)/(x!(8 - x)!)*((1)/(6) )^(A)*((5)/(6) )^(8-A) } \right. for A=0,1, ...8$

hence, p(6 twice) implies P(A=2)

that is P(2) substitute A = 2

$p(2) = \left \{ {(8!)/(2!(8 - 2)!)*((1)/(6) )^(2)*((5)/(6) )^(8-2) } \right. for A=0,1, ...8$

$p(2)=(8!)/(2!6!) *((1)/(6) )^(2) *((5)/(6) )^(6)$

p(2) = 0.2605

b. If B represent the number of times an odd number comes up. For the fair die the probability that an odd number comes up is 0.5.

Thus B ~ Bin(8, 1/2 )

The probability mass function of the random variable B is given by

$p(B) = \left \{ {(8!)/(B!(8 - B)!)*((1)/(2) )^(B\n)*((1)/(2) )^(8-B) } \right. for B=0,1, ...8$

hence p(odd comes up 5 times) is

$p(x=5) = p(2)=(8!)/(5!3!) *((1)/(2) )^(5) *((1)/(2) )^(3)$

p(5) = 0.2188

c. let the mean no of times a 6 comes up be μₐ

and let the total number of outcomes be n

using the formula μₐ = nρₐ

μₐ = 8 * 1/6

= 1.33

d. let the mean nos of times an odd nos comes up beμₓ

let the total outcomes be n = 8

let the probability odd be pb = 1/2

μₓ = npb

= 8 * (1/2)

= 4

e. the standard deviation of a random variable A is given as follows

σₐ $= √(np(1-p))$

where p = 1/6 (prob 6 outcome)

n = total outcomes = 8

$= \sqrt{8*(1)/(6)*(5)/(6) }$

= 1.0540

f. the standard dev of the binomial random variable Y is given by

σ $= √(np(1-p))$

where p = 1/2 and n = 8

= $\sqrt{8*(1)/(2) *(1)/(2) }$

= 1.4142

3 Which value of x satisfies the equation
5(2x - 9) + 3 =-

Answers

Answer:

Step-by-step explanation:

5(2x-9)+3

10x - 45 +3

10x - 42

x- 4.2

Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gender of any other children find the probability of at most three boys in ten births

Answers

The probability of at most three boys in ten births is approximately 0.17139, or about 17.14%.

What is Probability?

It is a branch of mathematics that deals with the occurrence of a random event.

This is a binomial probability problem with n = 10 (number of births) and p = 0.5 (probability of a boy or a girl).

We want to find the probability of at most three boys in ten births, which is equivalent to finding the probability of 0, 1, 2, or 3 boys.

To calculate this probability, we can use the binomial probability formula:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= 0.00098 + 0.00977 + 0.04395 + 0.11719

= 0.17139

Therefore, the probability of at most three boys in ten births is approximately 0.17139, or about 17.14%.

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Answer:

Step-by-step explanation:

This is a binomial distribution

The probability of at most 3 boys=

P(exactly 0 boys)+P(exactly 1 boy)+P(exactly 2 boys)+P(exactly 3 boys)

.171875

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