Answer:
y=3x+5
Step-by-step explanation:
He starts out with 5 pages already written then every hour after that he writes 3 more so plug in any amount of hours in for x and you will find how many pages he's written plus the 5 that he started out with.
Answer:
4%
Step-by-step explanation:
264 interest/3 years=88 interest/year
principal x interest rate =interest/year
2200 x interest rate =88
interest rate =88/2200
interest rate =.04 or 4%
Which of these sentences is always true for a parallelogram?
Answer:
parallelograms are shapes that have 2 sets of parallel sides. for example, squares, rectangles, and rhombuses are all types of parallelograms
To find:
(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates
(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates
Solution:
(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:
Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,
That is, the equation of the sphere in cartesian coordinates is,
Now, the cylindrical coordinate system is represented by
The relation between cartesian and cylindrical coordinates is given by,
Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,
This is the required equation of the given sphere in cylindrical coordinates.
(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.
That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,
Here, it is given that the center is at origin & radius is 1. That is, here, we have, . Then the equation of the cylinder in cartesian coordinates is,
Now, the spherical coordinate system is represented by
The relation between cartesian and spherical coordinates is given by,
Thus, the equation of the cylinder can be rewritten in spherical coordinates as,
(As )
Note that represents the distance of a point from the origin, which is always positive. represents the angle made by the line segment joining the point with z-axis. The range of is given as . We know that in this range the sine function is positive. Thus, we can say that is always positive.
Thus, we can square root both sides and only consider the positive root as,
This is the required equation of the cylinder in spherical coordinates.
Final answer:
(a) The equation of the given sphere in cylindrical coordinates is
(b) The equation of the given cylinder in spherical coordinates is
To find the value of w in terms of x and y, we need to substitute the given values of x and y into the equation for w. First, we are given the equation .
Let's simplify this equation before substituting it into the equation for w. Expanding the equation, we have: Now we can substitute the value of x into the equation for w. w Substituting the value of x from the earlier equation: w
At this point, we can further simplify the equation by dividing both the numerator and denominator by 3: wTherefore, the value of w in terms of x and y is wn summary: Starting with x we substituted the value of x into the equation for w and simplified to obtain w
To know more about denominator visit:
#SPJ2
Answer:
V= 22-2t
Step-by-step explanation:
I guess the alphabet should be v instead of y. So I am working using v
The rate at which water is draining from the tank is 2gallons/hour. This is the rate of water removal from the tank. So after an hour, 2 × 1= 2 gallons would have drained. After 5 hours, 2×5 =10 gallons would have drained
Therefore to obtain the amount of water in gallons that have been removed from the tank, you will multiply the rate by the time in hours after which the draining started.
Amount (gallons) =2×t
The amount of water remaining in the tank will be obtained by subtracting the amount of water drained after some hour (2×t) from the initial amount of water in the tank (22)
Therefore, the amount of water present in the tank (v)= 22-2t or 2(11-t) gallons
The formula to express volume of the water v in terms of time t is v = 22 - 2t, where 22 is the initial volume and 2t represents the rate at which the water is draining.
This problem is a mathematical representation of a real-world scenario using a linear equation. The volume of water v in the tank can be represented in terms of time t through the equation v = 22 - 2t. This equation illustrates the initial volume of water in the tank (22 gallons) and accounts for the constant rate at which the water is draining (2 gallons per hour).
When time t = 0 (meaning no time has passed since the water started draining), the volume of water v = 22 (the initial volume). As time increases, the volume gradually decreases at a rate of 2 gallons per hour, represented by the term -2t.
#SPJ3
half person).
Answer:
40.62
Step-by-step explanation:
that's the answer I got