MATHEMATICS HIGH SCHOOL

6. If RT = 4x, find the value of x and RS. x= RS = S RT = *

Answers

Answer 1

Answer:

Answer: 4

4x = 4

S RT = 4

Answer = 4

i am not so sure.

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Use the Quadratic Formula to solve

x²-13x+42=0

Answers

Answer:

x1=7,

x2=6

Step-by-step explanation:

x²-13x+42=0

a=1, b=-13, c=42

x1,2=(-b+-sqrt(b^2-4ac)) /2a

x1,2=(-(-13)+-sqrt((-13)^2-4*1*42))/2*1

x1,2=(13+-sqrt (169-168))/2

x1,2=(13+-sqrt(1))/2

x1,2=(13+-1)/2

x1=(13+1)/2, x2=(13-1)/2

x1=14/2, x2=12/2

x1=7, x2 =6

Stephanie finances $423,000 with a 20/5 balloon mortgage at 4.45%. How much will she pay for principal and interest over the life of the loan? Can someone show me how to solve the answer?A. $508,077.56
B. $509,378.67
C. $510,674.71
D. $505,422.01

Answers

The answer is C I think
Hope this helps :)

it is b.509,378.67
just add then multiply

How do you find the area of a hexagon?

Answers

you break it up into triangles, and from there you multiply 180 by the number of triangles in the hexagon (should be 4 triangles).

you would have to do length times the width or count all the sides.

Identify the number of solutions or zeros

2x^2+5x-9=0

Answers

There are going to be two solutions because the "biggest" x is x^2 but you can factor to find what they actually are.

Final answer:

The quadratic equation 2x^2+5x-9 = 0 has two solutions or zeros, which may be real or complex. They can be found using the quadratic formula: x = [-5 + sqrt(97)]/4 and x = [-5 - sqrt(97)]/4.

Explanation:

The equation given is 2x^2+5x-9=0, which is a quadratic equation. The solutions or zeros of a quadratic equation can be found using the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)]/2a. Here, a=2, b=5, and c=-9.

Let's substitute these values into the formula:

x = [-(5) ± sqrt((5)^2 - 4*2*(-9))]/2*2

x = [-5 ± sqrt(25 + 72)]/4

x = [-5 ± sqrt(97)]/4

Therefore, this equation has "two solutions" or zeros, which are x = [-5 + sqrt(97)]/4 and x = [-5 - sqrt(97)]/4.

Learn more about Quadratic Equations here:

brainly.com/question/30098550

#SPJ2

Find 4 consecutive even integers whose sum is 156?

Answers

x+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]

Answer: The integers are 36, 38, 40, and 42

Step-by-step explanation:

156/2=78

Find even integers by dividing that by two. 39.

So the two middle integers are 38 and 40.

You can go from there.

Rita has deposited $1000 in a bank account. At the end of each year, the bank posts interest to her account in the amount of 5% of the balance, but then takes out a $10 annual fee.