A cat is being chased by a dog. Both are running in a straight line at constant speeds. The cat has a head start of 3.8 m. The dog is running with a speed of 8.9 m/s and catches the cat after 6.0 s. How fast did the cat run?
Answers
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t,
= 49.6/6 = 8.267 m/s
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to mack boats float
Explanation:
without it the boats will sink to the bottom
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