The metal plate will have a net positive charge of +Q. This is due to charging by induction when a +Q charge is brought near it while grounded. Opening the switch before removing the charge leaves the induced +Q charge on the plate.
The metal plate's charge after a
+Q
charge is brought near it, the switch is opened and the charge is removed can be explained by understanding the process of
charging by induction
and the behavior of
charge on a conductor
. When the +Q charge is brought near the metal plate, it induces a -Q charge on the plate's closest surface due to the opposite charge attraction. This leaves an equal +Q charge on the farthest surface of the metal plate, as charges inside a conductor distribute to the outer surfaces in static equilibrium. When the switch connecting the plate to ground is opened, the +Q charge on the far side of the plate can't flow to ground and remains on the plate. Removing the +Q charge after that doesn't change the plate's charge as the system is no longer closed; it is now a
net positive charge
of +Q on the metal plate.
#SPJ12
A. For velocity, you must have a number, a unit, and a direction.
B. The SI units for velocity are m/s2.
C. The symbol for velocity is .
D. To calculate velocity, divide the displacement by time.
just took the quiz its A C and B
Answer:
5N itself because every action has an equal and opposite reaction
A. the same direction as the current.
B. a clockwise direction.
C. a counterclockwise direction.
D. the direction opposite to the current.
Answer: b. a clockwise direction
Explanation: just took the test