A beam of white light goes from air into water at an incident angle of 84.0∘. At what angles are the red 660 nm and violet 410 nm parts of the light refracted? Red light in water has an index of refraction equal to 1.331 and that of violet light is 1.342.

Answers

Answer 1

Answer:

The angle at which the light got refracted is known as the angle of refraction. The angle of refraction of red light is 48.3°. While the angle of refraction of Violet light is 47.8°.

What is snell law?

"The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given color and for a given set of media,

According to Snell's law. The formula for Snell's law is

$\rm {n= (sini)/(sinr) }$

i is the incidence angle

r is the refractionangle.

n is the refractive index of the medium

For red light,

$\rm {n= (sini)/(sinr) }\n\n\rm {1.331= (sin84^0)/(sinr)\n$

$\rm{sinr=(sin84^0)/(1.331)}$

$\rm r = sin^(-1)(0.7472)$

$\rm r = 48.3^0$ $\rm r = 47.8^0$

Hence the angle of refraction of red light is 48.3

For violet light,

$\rm {n= (sini)/(sinr) }\n\n\rm {1.342= (sin84^0)/(sinr)\n$

$\rm{sinr=(sin84^0)/(1.342)}$

$r = sin^(-1)(0.7411)$

Hence the angle of refraction of Violet light is 47.8°.

To learn more about snell's law refer to the link;

brainly.com/question/10112549

Answer 2

Answer:

Red light has an angle of refraction of 48.3°.

Violet light has an angle of refraction of 47.8°.

Explanation:

From Snell's law of refraction, the refractive index is the ratio of the sine of the angle of incidence to the sine of the angle of refraction.

$n=(\sin i)/(\sin r)$

For red light in water,

$1.331=(\sin 84)/(\sin r)$

$\sin r=(\sin 84)/(1.331)=0.7472$

$r=\sin^(-1)0.7472=48.3}$

For violet light in water,

$1.342=(\sin 84)/(\sin r)$

$\sin r=(\sin 84)/(1.342)=0.7411$

$r=\sin^(-1)0.7411=47.8}$

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To learn more about Distance and Displacement follow

brainly.com/question/127432

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