Answer:
Following are the code to the given question:
user_num = int(input())#defining a variable user_num that takes input from user-end
x = int(input())#defining a variable x that takes input from user-end
for j in range(3):#defining for loop that divides the value three times
user_num = user_num // x#dividing the value and store integer part
print(user_num)#print value
Output:
2000
2
1000
500
250
Explanation:
In the above-given program code two-variable "user_num and x" is declared that inputs the value from the user-end and define a for loop that uses the "j" variable with the range method.
In the loop, it divides the "user_num" value with the "x" value and holds the integer part in the "user_num" variable, and prints its value.
∃x (P(x) ∧ D(x))
Negation: ¬∃x (P(x) ∧ D(x))
Applying De Morgan's law: ∀x (¬P(x) ∨ ¬D(x))
English: Every patient was either not given the placebo or not given the medication (or both).
(a) Every patient was given the medication.
(b) Every patient was given the medication or the placebo or both.
(c) There is a patient who took the medication and had migraines.
(d) Every patient who took the placebo had migraines. (Hint: you will need to apply the conditional identity, p → q ≡ ¬p ∨ q.)
Answer:
P(x): x was given the placebo
D(x): x was given the medication
M(x): x had migraines
Explanation:
(a) Every patient was given the medication
Solution:
∀x D(x)
∀ represents for all and here it represents Every patient. D(x) represents x was given the medication.
Negation:¬∀x D(x).
This is the negation of Every patient was given the medication.
The basic formula for De- Morgan's Law in predicate logic is:
¬(P∨Q)⇔(¬P∧¬Q)
¬(P∧Q)⇔(¬P∨¬Q)
Applying De Morgan's Law:
∃x ¬D(x)
∃ represents there exists some. As D(x) represents x was given the medication so negation of D(x) which is ¬D(x) shows x was not given medication. So there exists some patient who was not given the medication.
Logical expression back into English:
There was a patient who was not given the medication.
(b) Every patient was given the medication or the placebo or both.
Solution:
∀x (D(x) ∨ P(x))
∀ represents for all and here it represents Every patient. D(x) represents x was given the medication. P(x) represents x was given the placebo. V represents Or which shows that every patient was given medication or placebo or both.
Negation: ¬∀x (D(x) ∨ P(x))
This is the negation or false statement of Every patient was given the medication or the placebo or both.
Applying De Morgan's Law:
∃x (¬D(x) ∧ ¬P(x))
∃ represents there exists some. As D(x) represents x was given the medication so negation of D(x) which is ¬D(x) shows x was not given medication. As P(x) represents x was given the placebo so negation of P(x) which is ¬P(x) shows x was not given placebo. So there exists some patient who was neither given medication nor placebo.
Logical expression back into English:
There was a patient who was neither given the medication nor the placebo.
(c) There is a patient who took the medication and had migraines.
Solution:
∃x (D(x) ∧ M(x))
∃ represents there exists some. D(x) represents x was given the medication. M(x) represents x had migraines. ∧ represents and which means patient took medication AND had migraines. So the above logical expression means there exists a patient who took medication and had migraines..
Negation:
¬∃x (D(x) ∧ M(x))
This is the negation or false part of the above logical expression: There is a patient who took the medication and had migraines.
Applying De Morgan's Laws:
∀x (¬D(x) ∨ ¬M(x))
∀ represents for all. As D(x) represents x was given the medication so negation of D(x) which is ¬D(x) shows x was not given medication. As M(x) represents x had migraines so negation of ¬M(x) shows x did not have migraines. ∨ represents that patient was not given medication or had migraines or both.
Logical expression back into English:
Every patient was not given the medication or did not have migraines or both.
(d) Every patient who took the placebo had migraines.
Solution:
∀x (P(x) → M(x))
∀ means for all. P(x) represents x was given the placebo. M(x) represents x had migraines. So the above logical expressions represents that every patient who took the placebo had migraines.
Here we are using conditional identity which is defined as follows:
Conditional identity, p → q ≡ ¬p ∨ q.
Negation:
¬∀x (P(x) → M(x))
¬∀ means not all. P(x) implies M(x). The above expression is the negation of Every patient who took the placebo had migraines. So this negation means that Not every patient who took placebo had migraines.
Applying De Morgan's Law:
∃x (P(x) ∧ ¬M(x))
∃ represents there exists some. P(x) represents x was given the placebo. ¬M(x) represents x did not have migraines. So there exists a patient who was given placebo and that patient did not have migraine.
Logical expression back into English:
There is a patient who was given the placebo and did not have migraines.
The program that prompts the user to enter a Social Security number in the format ddd-dd-dddd, where d is a digit can be implemented in Python using regular expressions. The regular expression pattern for the SSN format can be used to validate the input.
Pythons code:
```python
import re
ssn_pattern = re.compile(r'^\d{3}-\d{2}-\d{4}$')
ssn = input("Enter your Social Security Number (format: ddd-dd-dddd): ")
if ssn_pattern.match(ssn):
print("Valid SSN")
else:
print("Invalid SSN")
```
In the above code, we first import the `re` module to work with regular expressions.
We then define the regular expression pattern for the SSN format as `^\d{3}-\d{2}-\d{4}$`. This pattern matches any string that starts with three digits, followed by a hyphen, then two digits, another hyphen, and finally, four digits.
We then prompt the user to enter their SSN using the `input()` function. We then check if the entered SSN matches the pattern using the `match()` function of the regular expression object `ssn_pattern`.
If the SSN matches the pattern, we print "Valid SSN". Otherwise, we print "Invalid SSN".
Know more about SSN,
#SPJ4
ssn = input("Enter a valid Social Security number: ")
dashes = 0
nums = 0
message = "Invalid SSN"
if len(ssn) == 11:
for x in ssn:
if x.isdigit():
nums += 1
elif x == "-":
dashes += 1
if nums == 9 and dashes == 2:
message = "Valid SSN"
print(message)
I wrote my code in python 3.8. I hope this helps!
operator
b.
mathematical expression
c.
variable
d.
Boolean expression
Answer:
Boolean expression
Explanation:
The operator '&&' is called AND operator. it provide the output base on the Boolean value on each side of AND operator.
it has four possible values:
First Boolean is TRUE and Boolean is TRUE, then result will be TRUE.
First Boolean is TRUE and Boolean is FALSE, then result will be FALSE.
First Boolean is FALSE and Boolean is TRUE, then result will be FALSE.
First Boolean is FALSE and Boolean is FALSE, then result will be FALSE.
Therefore, the correct option is Boolean expression.
Answer:
sample output
Enter f0 = 440
440.0,466.1637615180899, 493.8833012561241,
523.2511306011974, 554.3652619537443
Explanation:
import math // math library
def RaiseToPower(): // RaiseToPower method
r = math.pow(2,1/12) //r = 2^(1/12)
f0 = float(input('Enter f0 : ')) //input from user
//a key has a frequency,sy f0
print(f0,end=' ') //Display statement
for n in range(1,5): //Iterate the loop up to the next 4 higher key Hz
n = f0 * math.pow(r,n) //calculate the fn value
print(fn,end=' ') //Display statement
RaiseToPower() //Call RaiseToPower method
Answer:
The advantage and the disadvantage of the relevant query are illustrated in the explanation in the paragraph below.
Explanation:
Advantage:
Disadvantage: