Answer:
Benzoic acid= 37.16%
Naphthalene = 24.43%
3-Nitroaniline= 29.38%
Explanation:
Data given:
percentage recovery of benzonic acid = 9.75/26.24 * 100 = 37.16%
Percentage recovery of napthalene = 6.41/26.24 * 100 = 24.43%
Percentage recovery of 3-nitroaniline = 7.71/26.24 * 100 = 29.38%
a. HCI
b. KOH
c. HNO
d. Mg(OH),
Answer and Explanation:
1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)
on the other hand
Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.
2. The Chemical name and nature of acid is shown below:-
Nature Chemical Name
a. HCl Acidic Hydrochloric Acid
b. KOH Basic Potassium hydroxide
c. HNO Acidic Nitric Acid
d. Mg(OH)2 Basic Magnesium hydroxide
highland
it is actually science on the subject but it doesn't have that option.
marine west coast
Mediterranean
subarctic
tropical wet-dry
Marine west coast and Mediterranean are the types of temperate climates, due to the dispersion of precipitation throughout the year, temperate marine climates are typically distinguished by a notable lack of dry season, hence options D and E are correct.
Temperate climates are regions with moderate annual or seasonal rainfall, intermittent drought, mild to warm summers, and cool to cold winters.
Humid subtropical, marine west coast, Mediterranean are the phrases that clearly identified with temperate marine climates.
Geographically speaking, the moderate climates of Earth are found in the middle latitudes, which are halfway between the tropics and the poles.
Therefore, options D and E are correct.
Learn more about temperate climates, here:
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Answer:
Humid Continental
Marine west coast
Mediterranean
subarctic
Explanation:
just did assignment on edge
The intermolecular forces that act between chlorine monofluoride (ClF) and hydrogen bromide (HBr) are dipole-dipole interactions. These types of forces result from the attraction between polar molecules.
The intermolecular forces that act between a chlorine monofluoride (ClF) molecule and a hydrogen bromide (HBr) molecule are
dipole-dipole interactions
. A
dipole-dipole interaction
is a type of force that results from the attraction between polar molecules. Since ClF and HBr are both polar molecules, they exhibit this kind of interaction. For instance, the positive end of the polar ClF molecule would be attracted to the negative end of the polar HBr molecule, and vice versa, leading to a
dipole-dipole interaction
.
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Between chlorine monofluoride and hydrogen bromide, the intermolecular forces present are dipole-dipole forces and London dispersion forces due to their polar nature and instantaneous polarizations of electron clouds respectively.
The intermolecular forces that act between a chlorine monofluoride molecule and a hydrogen bromide molecule are primarily the dipole-dipole forces. Dipole-dipole forces are attractive forces that occur between the positive end of one polar molecule and the negative end of another polar molecule. Both chlorine monofluoride and hydrogen bromide are polar molecules, and as such, they interact through dipole-dipole forces. Apart from this, there exists London dispersion forces which are weak forces resulting from instantaneous polarizations of electron clouds in molecules. Hence, between chlorine monofluoride and hydrogen bromide, both dipole-dipole forces and London dispersion forces act.
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B.) Positively charged
C.) Strongly ionic
D.) Negatively charged
Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
To calculate the final molarity of acetate anion in the solution, consider the dissociation of lead(II) acetate and the presence of ammonium sulfate. When ammonium sulfate is added, it reacts with the lead(II) cations, leaving only the acetate anions in the solution. The final concentration of acetate anions is therefore the same as the initial concentration.
To calculate the final molarity of acetate anion in the solution, we need to consider the dissociation of lead(II) acetate and the presence of ammonium sulfate. Lead(II) acetate will dissociate into lead(II) cations (Pb2+) and acetate anions (CH3COO-) in solution. However, when ammonium sulfate is added, the sulfate anions (SO42-) react with the lead(II) cations, forming lead(II) sulfate and removing them from solution. This leaves us with only the acetate anions.
First, calculate the concentration of the acetate anions in the lead(II) acetate solution. Then subtract the concentration of the acetate anions that reacted with the lead(II) cations to form lead(II) sulfate. This will give us the final concentration of acetate anions in the solution.
Let's assume we have an initial concentration of lead(II) acetate of X M. The dissociation of lead(II) acetate can be represented as:
Pb(CH3COO)2(s) ⇌ Pb2+(aq) + 2CH3COO-(aq)
Since we assume the volume of the solution doesn't change when the lead(II) acetate is dissolved, the initial concentration of acetate anions is also X M.
When ammonium sulfate is added, it reacts with the lead(II) cations according to the reaction:
Pb2+(aq) + SO4^2-(aq) ⇌ PbSO4(s)
Since the concentration of lead(II) sulfate is negligible, we can assume that all the lead(II) cations react with the sulfate anions. This removes the lead(II) cations from solution, leaving us with only the acetate anions.
Therefore, the final concentration of acetate anions is still X M.
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Answer
A. oxidation or reduction of an element
Explanation
A half reaction can be either oxidation or reduction reaction from a REDOX reaction.