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Mark had 3/2 cans of paint and used 1/2 can for his room. what fraction of the paint did he use

Answers

Answer 1

Answer:

Given:

Mark had $(3)/(2)$ cans of paint and used $(1)/(2)$ can for his room.

To find:

The fraction of the paint did he use.

Solution:

Total paint = $(3)/(2)$ cans

Paint used = $(1)/(2)$ can

The fraction of the paint did he use is:

$\text{Required fraction}=\frac{\text{Paint used}}{\text{Total paint}}$

$\text{Required fraction}=((1)/(2))/((3)/(2))$

$\text{Required fraction}=(1)/(3)$

Therefore, Mark use $(1)/(3)$ of the paint.

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(Functions and Relations) Answer getting brainliest!!

Answers

Answer:

Step-by-step explanation:

Have a nice day

PLZ HELP FAST looks easy

Answers

Answer:

135

180

225

Step-by-step explanation:

It represents a function because each element in the domain is matched with exactly one element in the range.

I don’t get it ? How are you supposed to do it

Consider the case0502 data from Sleuth3. <<< This is the data. Sleuth3 is preloaded into R studio.Dr Benjamin Spock was tried in Boston for encouraging young men not to register for the draft. It was conjectured that the judge in Spock’s trial did not have appropriate representation of women. The jurors were supposed to be selected by taking a random sample of 30 people (called venires), from which the jurors would be chosen. In the data case0502, the percent of women in 7 judges’ venires are given.

a. Create a boxplot of the percent women for each of the 7 judges. Comment on whether you believe that Spock’s lawyers might have a point.

b. Determine whether there is a significant difference in the percent of women included in the 6 judges’ venires who aren’t Spock’s judge.

c. Determine whether there is a significant difference in the percent of women incuded in Spock’s venires versus the percent included in the other judges’ venires combined. (Your answer to a. should justify doing this.)

Answers

Answer:

Consider the following calculations

Step-by-step explanation:

The complete R snippet is as follows

install.packages("Sleuth3")

library("Sleuth3")

attach(case0502)

data(case0502)

## plot

# plots

boxplot(Percent~ Judge, data=case0502,ylab="Values",

main="Boxplots of the Data",col=c(2:7,8),horizontal=TRUE)

# perform anova analysis

a<- aov(lm(Percent~ Judge,data=case0502))

#summarise the results

summary(a)

### we can use the independent sample t test here

sp<-case0502[which(case0502$Judge=="Spock's"),]

nsp<-case0502[which(case0502$Judge!="Spock's"),]

## perform the test

t.test(sp$Percent,nsp$Percent)

The results are CHECK THE IMAGE ATTACHED

> summary(a)

Df Sum Sq Mean Sq F value Pr(>F)

Judge 6 1927 321.2 6.718 6.1e-05 *** as the p value is less than 0.05 , hence there is a significant difference in the percent of women included in the 6 judges’ venires who aren’t Spock’s judge

Residuals 39 1864 47.8

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

t.test(sp$Percent,nsp$Percent)

Welch Two Sample t-test

data: sp$Percent and nsp$Percent

t = -7.1597, df = 17.608, p-value = 1.303e-06 ## as the p value is less than 0.05 , hence we reject the null hypothesis in favor of alternate hypothesis and conclude that there is a significant difference in the percent of women incuded in Spock’s venires versus the percent included in the other judges’ venires combined

alternative hypothesis: true difference in means is not equal to 0

95 percent confidence interval:

-19.23999 -10.49935

sample estimates:

mean of x mean of y

14.62222 29.49189

2Viviana is ordering carpet

for 16 square rooms in a

hotel. Each room will need

100 square feet of

carpet. What is the

length of 1 room?