the probability of a gorilla living longer than 14.3 years is 83.9%
Given :
The lifespans of gorillas in a particular zoo are normally distributed
Mean is 16 years and standard deviation is 1.7 years
Empirical rule diagram is attached below
We need to find the probability of a gorilla living longer than 14.3
Lets find out 14.3 lies in which standard deviation on left or right
mean is 16
14.3 lies on first standard deviation on left of mean 16
So we find out the area that covers after 14.3
The area after 14.3 is
the probability of a gorilla living longer than 14.3 years is 83.9%
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The probability of a gorilla living longer than 14.3 years is estimated to be 81.2% using the empirical rule.
To estimate the probability of a gorilla living longer than 14.3 years, we can use the empirical rule, also known as the 68-95-99.7% rule. According to this rule, for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
The average lifespan of gorillas in this zoo is 16 years, with a standard deviation of 1.7 years. To estimate the probability of a gorilla living longer than 14.3 years, we need to calculate the z-score. The z-score formula is:
z = (x - μ) / σ
where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.
Plugging in the values, we have:
z = (14.3 - 16) / 1.7
Solving this, we get a z-score of -0.88. Using a z-table or a calculator, we can find that the probability of a gorilla living longer than 14.3 years is approximately 0.812, or 81.2%.
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Answer:
2 barbies are left over
Step-by-step explanation:
5(5)=25
27-25=2
Leaving 2 barbies.
A. 1223 + 1
B. 6432 + 1
C. 6413 + 48y2 + 16y + 3
D. 6413 + 4812 + 12y + 1
$7.40 each?
Answer:
$222
Step-by-step explanation:
We need to find how many ream was used in the printing forts, to determine how much the College spent.
The catalog is 198 pages, back and front, which means, 1 leaf will take 2 pages. Therefore, 99 pages were used in printing 1 copy of the catalog.
No of pages that were used in printing 150 copies = 150*99 = 14,850 pages.
If 500 pages = 1 realm, therefore,
14,850 pages = 14,850/500 = 29.7.
Since, it's a full team that is sold, let's approximate the number of reams bought to be 30 reams.
If 1 ream costs $7.40, therefore,
30 reams = 30*7.40 = $222
To calculate the cost of printing the catalogs, you need to calculate the total number of pages printed, convert that into the number of reams needed, and then multiply by the cost per ream. The total cost comes out to $444.
This problem involves simple multiplication and division to calculate the cost. The catalog has 198 pages and they print 150 copies, so the total number of pages is 198*150=29,700 pages. Every ream has 500 pages so you need 29,700/500=59.4 reams. But, you can't have a part of a ream, so you should round up to 60 reams. Then you multiply the number of reams by the cost per ream: 60 reams*$7.40/ream=$444. Therefore, the cost to the college is $444.
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(a + 2)^2 + (b - 5)^2 + (c - 6)^2
c.
a + b + c -(-2 + 5 + 6)
b.
sqrt((a+2)^2+(b-5)^2+(c-6)^2)
d.
((a + 2) + (b - 5) + (c - 6))^2
Answer:
b. sqrt(a+2)^2+(b-5)^2+(c-6)^2
Step-by-step explanation:
Use distance formula
sqrt (a-(-2)^2 + (b-5)^2 + (c-6) ^2
sqrt (a+2)^2 +(b+5)^2 + (c-6)^2
Answer:
B
Step-by-step explanation:
took it on edge, it's the right answer :)
Amy used 13% of the total milk in the container.
Dan used 0.14 of the total milk in the container.
Mike used 0.5 gallon of the total milk in the container.
Who used the greatest amount of milk from the container? Show your work and explain your answer in words.
Must use inverse operations
I'm not sure what your teacher means by "must use inverse operations".
Anyways, Amy uses 13% of the total milk (6 gallons). So she uses 0.13*6 = 0.78 gallons.
Then we're told that Dan used 0.14 of the total milk. So 0.14*6 = 0.84 to indicate Dan used more than Amy. Dan also used more than Mike because 0.84 gallons is larger than 0.5 gallons.
Answer:
No correlation
Step-by-step explanation:
Hey there! :)
This has no correlation because all the points are spread out throughout the graph making no correlation.
Answer:
D no correlation
Step-by-step explanation:
too many scattered dot all over the place if its some going up down its NO CORRELATION!!!