MATHEMATICS COLLEGE

Give two examples of addition of two mixed numbers with different denominators
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Answers

Answer 1

Answer:

Answer:

First Example: 3 1/2 + 4 3/4, Second Example: 6 3/8 + 7 9/15

Extra Example: 8 4/20 + 3 5/10

Step-by-step explanation:

First Example:

1/2 + 3/4

1/2 is equal to 2/4 so it is now compatible to be added to 3/4.

2/4 + 3/4

= 5/4

Now for the mixed numbers since its 3 and 4, 3 + 4 = 7.

Final answer is 7 5/4.

Second Example:

3/8 + 9/15

9/15 can be reduced to 3/5

Now the equation is 3/8 + 3/5

= 15/40 + 24/40 is an equivalent equation

15/40 + 24/40

= 39/40

Now for the mixed numbers since its 6 and 7, 6 + 7 = 13

Final answer is 13 39/40.

I am going to include one last example just in case you need one:

Third Example:

4/20 + 5/10

We can reduce these to

1/5 + 1/2

= 2/10 + 5/10 is the equivalent equation

2/10 + 5/10

= 7/10

Now for the mixed numbers since its 8 and 3, 8 + 3 = 11.

Final answer is 11 7/10.

I Hope this helps!

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Which is the equation of an ellipse centered at the origin with foci on x-axis, x-intercepts +7, -7 and y-intercepts +2, -2?

Answers

we know that
foci on x-axis-------> is a ellipse with horizontal major axis

the equation is
(x²/a²)+(y²/b²)=1

major axis is the x-axis with length 2a
2a=14--------> a=7

minor axis is the y-axis with length 2b
2b=4-----> b=2

the equation is
(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1

the answer is
(x²/49)+(y²/4)=1

see the attached figure

Answer:

It's B on edge.

Step-by-step explanation:

Solve the system of equations.

6x - 5y = 15

X= y + 3

Answers

point form (1, -2)
equation form x=1, y=-2

Jamal is comparing his transportation options for an upcoming trip. He’s considering a rental car and a taxi service. Based on his planned routes during his trip, he expects a taxi service would cost about $128. Jamal could also get a rental car for a daily rate and unlimited miles. If Jamal’s trip will last 4 days and he expects to pay about $24 for gas, which graph shows the range of car rental rates that would be cheaper than the taxi service?

Answers

Answer:

Graph A

Step-by-step explanation:

Say that the car rental rate stands for c dollars ( $ ). We know that Jamal's trip lasts for 4 days, paying $ 24 in expenses for gas, and $ 128 for taxi services. Based on these requirements for his trip the question asks for a graph that models this situation, but lets start with the inequality.

______

The big key here is the part " which graph shows the range of car rental rates that would be cheaper than the taxi service. " Our inequality must thus have the variable " c " on the same side as the payment for gas ($ 24 ), and must be less than the taxi service ( $ 128 ), or in other words a less than sign. Another point is the car rental rate. We know it stands for c, but it is dependent on the number of days. Hence we can conclude the following inequality,

24 + 4c < 128 - Subtract 24 from either side,

4c < 104 - Divide by 4 on either side, isolating c,

c < 26

The range of car rental rates that would be cheaper than the taxi service should be { c | 0 ≤ c < 26 }, knowing variable c stands for the car rental rates.

______

The graph that models this range should be the first one, option A. This graph is not accurate however, as it extends infinitely in the negative direction, and you can't have negative money, or rather be in debt - in this situation.

Answer:

A is the answer

Step-by-step explanation:

14. Taxi company A charges $2 per ride plus $0.25 per mile. Taxi company B charges $3 per ride plus $0.15 per mile. Which equation could be used to find the number of miles for which both companies cost the same for one ride? O A.2.25m = 3.15m B. 2 + 0.15m = 3 + 0.25m
C.2m +0.25 = 3m +0.15
D.2 + 0.25m = 3 + 0.15m

Answers

Answer:

So i beiieve the answer is B

Step-by-step explanation:

Because if you thinl about the ride for A is $2 plus 25 cents so its 2 plus 25m thats per mile and b 3 dollars and 15 so u keep adding up until u get the same from both equations if u need further explanation let me know

A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 52% chance, independently of each other. (Report answers accurate to 4 decimal places.)1. Find the probability that overbooking occurs.
2. Find the probability that the flight has empty seats.

Answers

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable X represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), p = 0.52

The random variable X thus follows a Binomial distribution with parameters n = 5 and p = 0.52.

(1)

Compute the probability of overbooking as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

$=P(X>3)\n\n={5\choose 4}(0.52)^(4)(1-0.52)^(5-4)+{5\choose 5}(0.52)^(5)(1-0.52)^(5-5)\n\n=0.175478784+0.0380204032\n\n=0.2134991872\n\n\approx 0.2135$

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

$=P(X<3)\n\n1-P(X\geq 3)\n\n=1-[{5\choose 3}(0.52)^(3)(1-0.52)^(5-3)+{5\choose 4}(0.52)^(4)(1-0.52)^(5-4)+{5\choose 5}(0.52)^(5)(1-0.52)^(5-5)]\n\n=1-[0.323960832+0.175478784+0.0380204032]\n\n=0.4625399808\n\n\approx 0.4625$

Thus, the probability that the flight has empty seats is 0.4625.

A segment has endpoints A (-1, 1) and B (8, 4) .If the segment is divided into four equal parts, the coordinates of the point closest to point A are _____?