Answer:
y = - 750
Step-by-step explanation:
Given
y = x³y² ← substitute x = - 5, y = - 3 into the expression
= × (- 5)³ × (- 3)²
= × - 125 × 9 ( cancel the 3 and 9 )
= 2 × - 125 × 3
= - 750
Answer: The 60th term of the arithmetic sequence -29, -49, -69, … is -1209.
Step-by-step explanation:
The given arithmetic sequence is -29, -49, -69, …
To find the 60th term of this sequence, we need to use the formula for the nth term of an arithmetic sequence:
a_n = a_1 + (n - 1)d
where a_n is the nth term of the sequence, a_1 is the first term of the sequence, n is the number of terms in the sequence, and d is the common difference between consecutive terms.
In this case, a_1 = -29 and d = -20 (since each term is 20 less than the previous term). We want to find a_60, so we substitute n = 60 into the formula:
a_60 = -29 + (60 - 1)(-20) = -29 + 59(-20) = -29 - 1180 = -1209
Therefore, the 60th term of the arithmetic sequence -29, -49, -69, … is -1209.
Please let me know if you have any other questions!
y=-2
-8x-4y+x
Answer:
-34
Step-by-step explanation:
first do substitution: -8 · 6 + -4 · -2 + 6
next do the multiplication: -48 + 8 + 6
add: -34
hope this helps!!!
Answer:
-34
Steps:
-8x - 4y + x
-8x + x = -7x (combine like terms)
-7x - 4y
-7(6) - 4(-2) (plug in the numbers)
-42 +8=
-34
:")
x=t-yz
x = Amount down
y = Money each month
z = Number of months
t = Total price
Rewrite the formula to solve for the amount of money Jeremy must pay each month.
Answer:
Step-by-step explanation:
Given: A formula that describes this scenario:
where, x = Amount down
y = Money each month
z = Number of months
t = Total price
To solve the formula for the amount of money Jeremy must pay each month i.e. y, first subtract t on both sides of the equation, we get,
Now, divide z on both sides, we get
The correct answer is:
Explanation:
We want to solve for the amount of money he pays each month. This is represented by y in the equation. This means we want to isolate y in the equation:
x = t - yz
We first want to subtract t from each side:
x - t = t - yz - t
x - t = -yz
Now we want to cancel the negative sign and z. We can isolate both of these at the same time; divide both sides by -z:
We can divide the numerator by the negative sign; this gives us