You have a rectangular yard that measures 16 feet long 14 feet wide. It is covered in grass except for the center, where there is a circular fountain with a diameter of 4 feet. What is the area of the grass portion of your yard? Round your answer to the nearest hundredth. is it (a) 131.43 ft.² (b) 173.74 ft² (c) 211.43 ft² (d) 263.74 ft²

Answers

Answer 1
Answer: the entire square of your yard is equal to 16*14
16*14=224 square feet
you have to find the area of the fountain and subtract it from the total yard to get just the area with grass
pi*2^2
pi*4=12.57 feet squared
224-12.57= C. 211.43 feet squared of grassy area


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A students' choir contains 25 children and only 5 of them play the piano. If a child is selected at random, what is the probability that the child DOES NOT play the piano? Select all the right answers.

Answers

Answer:

probability that the child DOES NOT play the piano

P(E^(-))  =(4)/(5)

Step-by-step explanation:

A students' choir contains 25 children

n(S) =25

The number of students play the piano =5

Let 'E' be the event of the child play the piano so n(E) =5

The probability of that the child play the piano

 P(E) = (n(E))/(n(S))

 P(E) = (5)/(25)= (1)/(5)

Let 'E⁻ be the event of the child play does not play the piano

P(E^(-)) = 1- P(E)

P(E^(-)) = 1- (1)/(5) =(4)/(5)

Conclusion:-

probability that the child DOES NOT play the piano

P(E^(-))  =(4)/(5)

What is the complement of the angle 178 degrees and 100 degrees

Answers

Complement - x \n \n 178 + x = 90 \n \n x = 90-178 = -88. \n\n\nComplement-y \n \n 100 + y = 90 \n \n y = 90-100 = -10

Thus, the complement of 178 is -88 degrees and complement of 100 is -10.
The\ complement\ of\ an\ angle\ \alpha \ is\ the\ angle\ 90^0- \alpha .\n\n \alpha =178^0\ \ \ \Rightarrow\ \ \ 90^0- \alpha =90^0-178^0=-88^0\n\n\alpha =110^0\ \ \ \Rightarrow\ \ \ 90^0- \alpha =90^0-110^0=-20^0

Every 1/2 hour Naomi streches her neck; every 1/3 hours she stretches her legs; and every 1/6 hour she streches her arms. Which parts of her body will Naomi strech when2/3 of an hour has passed?A- neck and legs
B- neck and arms
C- legs and arms
D- none

Answers

 The correct answer A. 

Keith is racing his little sister Pattie and has given her a 15 foot head start. She runs 5ft/sec and he is chasing at 8ft/sec. For how long can Pattie stay ahead of Keith? Write and solve an inequality and show your work. Plz Help!

Answers

Pattie runs at 5 ft/sec
She has got a head start of 15 feet.
So after 1 second, Pattie runs = (5+15) ft                                                   
                                                  = 20
ft
After 2 second Pattie runs = (20+5)ft
                                           = 25 ft
After 3 second Pattie runs = (25+5) ft
                                           = 30 ft
After 4 seconds Pattie runs = (30+5) ft
                                             = 35 ft
After 5 seconds Pattie runs = (35+5) ft
                                             = 40 ft
After 6 seconds Pattie runs  = (40+5) ft
                                             = 45 ft
Now Keith runs at 8 ft/sec
After 1 second Keith runs = 8 ft
After 2 second Keith runs = (8+8) ft
                                           = 16 ft
After 3 second Keith runs = (16+8) ft
                                           = 24 ft
After 4 second Keith runs = (24+8) ft
                                          = 32 ft
After 5 second Keith runs = (32+8) ft
                                           = 40 ft
After 6 second Keith runs = (40+8) ft
                                           = 48 ft
So Pattie will stay ahead of Keith upto 4 seconds. In the 5th second Pattie and Keith will be level and in the 6th second Pattie will be overtaken by Keith.


The total amount y (in dollars) in your savings account after buying x video games is represented by y=90-10x. You have $40 in your account after buying video games. How many video games did you buy?

Answers

5 video games bought.

Explanation:
Step one) identify all variables.
> y = money in bank acc AFTER buying (x) video games.
Step two) y = $40
Step three) substitute
> 40 = 90 - 10x.
Step Four) solve for x
> subtract 90 both sides.
-50 = -10x
DIVIDE by -10 on both sides ( to isolated x)
This equals 5 = x
x is number of video games bought meaning >> 5 video games bought :))

Final answer:

The equation y = 90 - 10x indicates the amount left in the savings account after buying x number of video games. Plugging in 40 for y and solving for x, it is found that 5 video games were purchased.

Explanation:

To find out the number of video games purchased, you need to solve the equation y = 90 - 10x for 'x' when 'y' is 40. This equation represents the total amount in your savings account (y) after buying x number of video games.

  1. Plug in 40 for 'y' in the equation:
    40 = 90 - 10x
  2. Subtract 90 from both sides of the equation:
    -50 = -10x
  3. Divide both sides by -10:
    5 = x

So, you bought 5 video games to have $40 left in your savings account.

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How many times would a coin have to show heads in 50 tosses to have an experimental probability of 20% more than the theoretical probability of getting heads?

Answers

The theoretical probability of getting heads is 50%. 50% of 50 is 25. So, 20 % more than 50% is 20% * 25 + 25 = 5 + 25 = 30. That means that the coin should show 30 heads fo have an experimental probability of 20% more than the theoretical probability. You can check that 30 out of 50 is 0.6. Which is 0.1 more than 0.5. And 0.1 is 20% of 0.5. Then 0.6 is 20% more than 0.5.

Final answer:

In a series of 50 coin tosses, a coin needs to land heads 30 times to have an experimental probability 20% greater than the theoretical probability.

Explanation:

The subject of focus here is the allusion to the theory of probability, particularly in relation to a fair coin flip. The theoretical probability of obtaining either heads or tails in a coin flip is 0.5. However, the student is interested in having an experimental probability 20% greater than the theoretical probability.

We can first calculate the theoretical counts of expected heads per 50 tosses, which is (0.5 * 50) = 25. This result represents the notion that if a coin is thrown 50 times, on average, will land heads 25 times based on the theoretical probability.

To achieve an experimental probability 20% greater than the theoretical probability, we need to find a count of heads that corresponds to a probability that is 20% more than 0.5 (the theoretical probability). This new probability is therefore 0.6 and the corresponding count of heads required would be (0.6 * 50) = 30. Hence, in 50 tosses, the coin would need to show heads 30 times to have an experimental probability 20% greater than the theoretical probability of getting heads.

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