Which of the following diagrams is the correct electron dot diagram for Ne?
Answers
Answer:
B.
Explanation:
The electron dot diagram which is also known as the Lewis electron dot diagram is a diagram that shows an atom's valence electrons by placing dots, which represent the valence electrons of the element, around the elements symbol
The element for which the electron dot diagram is found = Neon, Ne
The atomic number of neon, Ne = 10
The electronic configuration of neon = 1s²2s²2p⁶
The valence shell is the outermost shell having the highest value of the coefficient of the orbitals, n = 2s²2p⁶
The number valence electrons in neon = The number of electrons in the valency shell = 2 electrons + 6 electrons = 8 electrons
The number of valence electrons in neon = 8
Therefore, the electron dot diagram for neon will have 8 dots located around the Ne symbol, which gives option B
Related Questions
The decomposition of ammonium hydrogen sulfideNH4HS (s) <=> NH3 (g) + H2S (g)is an endothermic process. A 6.1589-g sample of the solid is placed in an evacuated 4.000-L vessel at exactly 24°C. After equilibrium has been established, the total pressure inside is 0.709 atm. Some solid NH4HS remains in the vessel.(a) What is the KP for the reaction?(b) What percentage of the solid has decomposed?(c) If the volume of the vessel were doubled at constant temperature, what would happen to the amount of solid in the vessel?
Copper(i) ions in aqueous solution react with nh3(aq) according to
The Top Thrill Dragster, a rollercoaster at Cedar Point in Ohio, soars through the air at 176ft/sec. How fast is this in mph?
The isotope 65Cu2+ has how many electrons and how many protons?
Answers
If the volume goes up, the pressure goes down.
Answer:
0.87
Explanation:
Answers
The volume of the gas at 127.0 °C is 321.28 ml.
What is volume?
The volume of any substance is the total space it occupies.
Given data is
V₁ is 400.0 mL
T₁ is 225.0ºC + 273 = 498 K
T₂ = 127.0ºC + 273 = 400 K
To find V₂
By Ideal gas law
Thus, the volume of the gas at 127.0 °C is 321.28 ml.
Learn more about volume, here:
T₁ = 225.0ºC + 273 = 498 K
V₂ = ?
T₂ = 127.0ºC + 273 = 400 K
V₁ / T₁ = V₂ / T₂
400.0 / 498 = V₂ / 400
498 x V₂ = 400 x 400
498 x V₂ = 160000
V₂ = 160000 / 498
V₂ = 321.28 mL
hope this helps!
Answers
Answers
450
Explanation:
edxdded gvt rgt gt tgrtrg
A: The rate of formation of R is one-half the rate of the disappearance of Z.
B: The rate of disappearance of Z is one-fourth of the rate of disappearance of X.
C: The rate of formation of R is double the rate of formation of S.
D: The rate of formation of S is double the rate of disappearance of X.
Answers
B: The rate of disappearance of Z is one-fourth of the rate of disappearance of X
Because as x -> 0, 4->0
z-> 0, 1->0
Answers
Final answer:
0.500 mole of any gas at standard temperature and pressure (STP) is equivalent to 11.2 liters. This is calculated using Avogadro's Law.
Explanation:
The quantity that represents 0.500 Mole at Standard Temperature and Pressure (STP) refers to the volume of gas. According to Avogadro's law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules, 1 mole of any gas at STP occupies a volume of 22.4 liters. Therefore, 0.500 mole of a gas at STP would occupy a volume of 11.2 liters.
Here's how you calculate this: Use Avogadro's law proportion, which is V1/n1 = V2/n2. Given n1 is 1 mole, V1 is 22.4 liters (which are standard values at STP) and n2 is 0.500 mole (your desired quantity), you can solve for V2 :
V2 = V1 * n2 / n1 = 22.4 L * 0.500 mol / 1 mol = 11.2 L.
So, 0.500 mole of any gas at STP would have a volume of 11.2 liters.
Learn more about Moles at STP here:
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