A distributor needs to mix some Terraza coffee that normally sells for $9.00 per pound with some Kona coffee that normally sells for $13.50 per pound to create 50 pounds of a mix that can sell for $9.54 per pound. How many pounds of each kind of coffee should they mix?
Answers
Answer:
Step-by-step explanation:
Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:
#lbs x $/lb = Total
T
K
Mix
Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:
#lbs x $/lb = Total
T 9
K 13.50
Mix
Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound
#lbs x $/lb = Total
T 9
K 13.50
Mix 50 9.54
Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:
#lbs x $/lb = Total
T x x 9 = 9x
K 50 - x x 13.50 = 675 - 13.50x
Mix 50 x 9.54 = 477
The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:
9x + 675 - 13.5x = 477 and
-4.5x = -198 so
x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.
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I'd be more than happy to do all of that, but I can't even start
until I see YOUR picture of the problem. That will show me
if circle-P and circle-q are overlapping, just touching, separate
from each other, same size, different sizes, their radii, and where
the points J and K are. THOSE are the little things I need to know
in order to get started.
You want to know the distance between J and K, but you haven't
given us one single distance or size of anything in the problem ...
nothing at all to work with. That right there makes it impossible.
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how many solutions (x,y) are there to the system of equations above ?
a none
b one
c two
d more than two
please explain how u know
Answers
Option B. one.
How do you know how many solutions a system of equations has?
A linear equation in two variables is an equation of the form ax + by + c = 0 where a, b, c ∈ R, a, and b ≠ 0. When we consider a system of linear equations, we can find the number of solutions by comparing the coefficients of the variables of the equations.
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55c+47m=197
c+m=3.8
c=-m+3.8
55(-m+3.8)+47m=197
-55m+209+47m=197
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m=1.5
maria drove 1.5hr or 1 and a half hr.
Maria : x
Carlos : y
7, 6, 15, 6, 10, 4, 3 ,11 ,1
State the median.
Answers
1,3,4,6,6,7,10,11,15
Answers
Answer:
h=3V/πr²
Step-by-step explanation:
- V= πr²h/3
- πr²h=3V
- h=3V/πr²
Answer:
3V / (pi r^2) = h
Step-by-step explanation:
V= pi r squared h/3
Multiply each side by 3
3V = pi r^2 h /3 * 3
3V = pi r^2 h
Divide each side by pi r^2
3V / (pi r^2) = pi r^2 h /( pi r^2)
3V / (pi r^2) = h