Step-by-step explanation:
1.(first second or third)
2)what is the vertical component of the velocity just before the ball strikes the ground?
3) what is the horizontal component of the velocity just before the ball strikes the ground?
4)how far from the base of the building did the ball strike the ground?
5) what is the speed of the ball just before it strikes the ground?
There are 5 large dogs and 3 small dogs
Let "S" be the number of small dogs
Let "L" be the number of large dogs
Given that There are a total of 8 small and large dogs
So we can frame a equation as:
number of small dogs + number of large dogs = 8
S + L = 8 ------- eqn 1
You realize there are 2 more large dogs than small dogs
Number of large dogs = 2 + number of small dogs
L = 2 + S -------- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "L" and "S"
Substitute eqn 2 in eqn 1
S + 2 + S = 8
2S + 2 = 8
2S = 6
Substitute S = 3 in eqn 2
L = 2 + 3 = 5
Thus there are 5 large dogs and 3 small dogs
Answer:
5 large dogs and 3 small dogs
Step-by-step explanation:
B) 41 minutes
C) 49 minutes
D) 51 minutes
The critical path in a project schedule is the longest sequence of tasks from start to finish and determines the minimum total duration for the project. Without the diagram, the correct duration from your multiple-choice options cannot be determined accurately. The correct answer represents the duration of the longest path from the given options.
Without the graphic showing the schedule networkdiagram for assembling a toy train set, providing an accurate answer would be difficult. Normally, in project management, a Critical Path represents the longest sequence of tasks (or activities) in a project schedule from start to finish. It determines the minimum total duration required to complete the project. You identify the critical path by adding the times for the activities in each sequence and determining the longest path in the project.
In this case, assuming that you have the diagram in front of you and you've calculated the total duration for all paths, one of the multiple choice options (A) 38 minutes, (B) 41 minutes, (C) 49 minutes, or (D) 51 minutes would represent the duration of the critical path in the network diagram.
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154°
64°
90°
Answer:
The other acute angle is 64°
Step-by-step explanation:
Given a right triangle in which the measure of one acute angle is 26°
we have to find the measure of the other acute angle.
Let the required acute angle is x
By angle sum property, the sum of all angles of triangle is 180°
Hence, the other acute angle is 64°
Answer:
a) 61.2, b) 38.4 and c) 4.98
Step-by-step explanation:
Given:
The mean width of 12 I-Pads is 5.1 inches.
The mean width of 8 Kindles is 4.8 inches.
Question asked:
a. What is the total width of the I-Pads?
b. What is the total width of the Kindles?
c. What is the mean width of the 12 I-Pads and 8 Kindles?
Solution:
As we know:
a) Thus, the total width of the I-Pads are 61.2 inches.
b) Thus, total width of the Kindles are 38.4 inches.
Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches
Combined number of observations = 12 + 8 =20
Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles Combined number of observations
Combined mean of width of the 12 I-Pads and 8 Kindles =
c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.
The total width of the iPads is 61.2 inches and for the Kindles, 38.4 inches. When calculated together, the mean width of the iPads and Kindles is 4.98 inches per device.
This question deals with the calculation of means (averages) and total values. To find the total width of the iPads, we multiply the mean width by the number of iPads:
5.1 inches * 12 iPads = 61.2 inches.
For the Kindles, we do the same:
4.8 inches * 8 Kindles = 38.4 inches.
To find the mean width of all the devices together, we add up the total widths and divide by the total number of devices:
(61.2 inches + 38.4 inches) / (12 iPads + 8 Kindles) = 99.6 inches / 20 devices = 4.98 inches/device.
#SPJ12