Answer:
Nhiệt dung riêng của đồng là
380
J
/
k
g
.
K
Explanation:
Given Mass of pure silver (Ag) = 265 mg
Silver chloride AgCl which is used in plating silver contains 75.27 % Ag
This means that:
A 100 mg of silver chloride contains 75.27 mg of silver
Therefore, the amount of silver chloride required to plate a sample containing 265 mg silver would correspond to:
265 mg Ag * 100 mg AgCl/75.27 mg Ag
= 352.1 mg AgCl
Answer:
0.35215 grams of silver chloride required to plate 265 mg of pure silver.
Explanation:
Mass of silver = 265 mg = 0.265 g
Moles of silver =
According to reaction, 2 moles of silver are obtained from 2 moles of silver chloride.
Then 0.002454 moles of silver will be obtained from :
of silver chloride
Mass of 0.002454 moles of silver chloride:
= 0.002454 mol × 143.5 g/mol = 0.35215 g
0.35215 grams of silver chloride required to plate 265 mg of pure silver.
b. Acid B has a larger K_a than acid A._______ will have a larger percent ionization.
c. A is a stronger acid than B. Acid B will have________ percent ionization than A.
Answer:
a. Acid B
b. Acid B
c. lower
Hope this helps you
Answer:
3056.25g
Explanation:
Problem here is to find the mass of Cu(NO₃)₂ to weigh out to make for the number of moles.
Given;
Number of moles = 16.3moles
Unknown:
Mass of Cu(NO₃)₂ = ?
Solution:
To find the mass of Cu(NO₃)₂, use the expression below;
Mass of Cu(NO₃)₂ = number of moles x molar mass
Let's find the molar mass;
Cu(NO₃)₂ = 63.5 + 2[14 + 3(16)]
= 63.5 + 2(62)
= 187.5g/mol
Mass of Cu(NO₃)₂ = 16.3 x 187.5 = 3056.25g
Answer:
4.88 Cals per degree celsius
Explanation:
We have taken heat of fusion of ice = 80 cals / g
We have taken speciic heat of water = 1 cal/g per degree celsius
In this experiment , let the heat capacity of calorimeter be X.
Heat gained by ice
heat gained in melting + heat gained in getting warmed
= mass x latent heat + mass x specific heat x rise in temperature
= 17.69 x 80 + 17.69 x 1 x ( 12.9 - 0 )
= 1643.4 Cals
Heat lost by water
= mass x specific heat x fall in temperature
98.67 x 1 x ( 28.77 - 12.9 )
= 1565.89 Cals
Heat lost by calorimeter
heat capacity x fall in temperature
X x ( 28.77 - 12.9 )
Heat gained = heat lost
1643.4 = 1565.89 +15.87X
X = 4.88 Cals per degree celsius
Answer:
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Explanation:
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1.27 × 10²⁴ atoms of nickel are contained in 2.11 moles of nickel. For every mole of a substance there are 6.022 × 10²³ representative particles of that substance. The amount of particles in one mole of substance is called Avogadro's number.
To convert from the number of moles to number of representative particles, the formula below may be used:
For this problem, the number of nickel atoms can be determined by plugging in the given values in the equation above:
Since the given only has three significant figures, the final answer with the correct number of significant figures is:
Keywords: moles conversion, Avogadro's number