One gram of a compound requires the following quantities of solvent to dissolve: 47 mL of water, 8.1 mL of chloroform, 370 mL of diethyl ether, or 86 mL of benzene. Calculate the solubility of the compound in these four solvents (as g/100 mL). Estimate the partition coefficient of the compound between chloroform and water, ethyl ether and water, and benzene and water. Which solvent would you choose to extract the compound from an aqueous solution

Answers

Answer 1
Answer:

Answer:

Chloroform.

Explanation:

Given,

Solvent requires 1g of compound per 100 mL

For water,

= 1g/47ml

= 2.1

For Chloroform,

= 1 g/8.1 mL

= 12.345679

For Diethyl ether,

= 1 g/370 mL

= 0.27

For Benzene,

=  1 g/86 mL

= 1.2

Partition coefficients:

Water = -

chloroform = 5.9

Diethyl = .13

Benzene  = .57

The solvent chloroform would be chosen for drawing out the compound out of an aqueous solution as it has the maximum solubility.

Answer 2
Answer:

Final answer:

The solubility of a compound in different solvents will determine its concentration in each solvent. The partition coefficient represents the relative solubility of a compound in two immiscible solvents. Chloroform would be the best choice to extract the compound from an aqueous solution.

Explanation:

The solubility of a compound is usually expressed as grams of solute per 100 mL of solvent. To calculate the solubility, you can use the following formula:

Solubility (g/100 mL) = (mass of solute / volume of solvent) * 100

Using this formula, the solubility of the compound in water is 47 g/100 mL, in chloroform is 97.53 g/100 mL, in diethyl ether is 2.70 g/100 mL, and in benzene is 1.16 g/100 mL.

The partition coefficient is a measure of the compound's solubility in two immiscible solvents. To calculate it, divide the solubility of the compound in one solvent by its solubility in another solvent. For example, the partition coefficient between chloroform and water would be:

Partition coefficient = Solubility in chloroform / Solubility in water = 97.53 g/100 mL / 47 g/100 mL = 2.07

The larger the partition coefficient, the more soluble the compound is in the first solvent compared to the second solvent. Based on the partition coefficients, chloroform would be the best choice to extract the compound from an aqueous solution.

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What is the electron pair geometry for a phosphine molecule, PH3? A) tetrahedral B) bent C) linear D) trigonal pyramidal E) none of the above

Answers

Final answer:

The electron pair geometry of a phosphine, PH3, molecule is tetrahedral, though the molecule itself takes on a trigonal pyramidal shape due to the presence of a lone pair of electrons on the phosphorus atom.

Explanation:

The electron pair geometry for a phosphine molecule, PH3, is tetrahedral. In PH3, the phosphorus atom is the central atom surrounded by three hydrogen atoms. However, it is important to note that the phosphorus atom also has a lone pair of electrons. The lone pair occupies more space than bonding pairs, causing the molecule to take on a trigonal pyramidal molecular geometry. Despite the molecular geometry, the electron pair geometry is considered tetrahedral because it accounts for all regions of electron density, including lone pairs.

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Final answer:

The electron pair geometry for a phosphine molecule (PH3) is tetrahedral. This refers to the spatial arrangement of regions of electron density around the central atom, phosphorus, which is bonded to three hydrogen atoms and has one lone pair of electrons.

Explanation:

The electron pair geometry for a phosphine molecule, PH3, is best described as tetrahedral. Even though the PH3 molecule is not tetrahedral, the electron pair geometry refers to the spatial arrangement of regions of electron density around the central atom, in this case, phosphorus. Phosphorus in the PH3 molecule is bonded to three hydrogen atoms and has one lone pair of electrons. These four regions of electron density adopt a tetrahedral arrangement to minimize electron-electron repulsion. Please note that the molecular structure of PH3 is trigonal pyramidal as lone pairs are not included while determining the molecular geometry.

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What is the chemical formula for the ionic compound formed by Au3+ and
HSO3-?

Answers

Answer:

The chemical formula for the ionic compound formed by Au3+ and

HSO3-compound  is Au(HSO3)3

Explanation:

The charge on Au ion is +3

And the charge on HSO3- is -1

Thus, the number of atoms required by HSO3- to complete its octate is 1. On the other hand Au has 3 excess ions and hence it is to be released to reach the stable state.

So three molecules of HSO3- will combine with one atom of Au 3+

Thus, the compound formed by these two is Au(HSO3)3

Final answer:

The chemical formula for the ionic compound formed by Au3+ and HSO3- is Au(HSO3)3, as ionic compounds are always neutral.

Explanation:

The ionic compound formed by Au3+ (Gold ion) and HSO3- (Bisulfite ion) must have a net charge of zero since ionic compounds are neutral. Hence, we need 3 bisulfite ions to balance out one gold ion, which gives us the chemical formula as Au(HSO3)3.

Indeed, the formation of ionic compounds is a fascinating process. It involves the transfer of electrons from one atom (usually a metal) to another (usually a nonmetal), resulting in the formation of ions. These ions are then attracted to each other due to their opposite charges, forming an ionic compound. In this case, the gold ion (Au3+) donates three electrons, which are accepted by three bisulfite ions (HSO3-). This results in a neutral compound, as the positive and negative charges balance each other out. The resulting compound, Au(HSO3)3, is an example of how elements can combine in specific ratios to form neutral compounds.

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After mixing sand with water, after awhile it settles to the bottom. WHY?

Answers

Answer:

Because the water is filled up with the sand every where

Explanation:

So the exess sand goes to the bottem

Answer:

Mass/Volume

Explanation:

The sand eventually makes it way to the bottom because of its mass/volume compared to the waters density. Just like while swimming in a pool, we sink to the bottom because of our mass/volume.

Question 16 Unsaved Which of the following diagrams represents the correct cycling of gases?A) Photosynthesis O2 Respiration CO2
B) Respiration O2 photosynthesis CO2
C) Photosynthesis H2 Respiration O2
D) Respiration CO2 photosynthesis H2

Answers

the answer is A:

Photosynthesis release O2 (oxygen)

then animals use oxygen for respiration and release Co2

Final answer:

The correct answer is A) Photosynthesis O2 Respiration CO2. Photosynthesis converts CO2 to O2, which is then used in respiration to be converted back into CO2. Both processes together create a continuous cycle.

Explanation:

The correct diagram that represents the cycling of gases between photosynthesis and respiration is A) Photosynthesis O2 Respiration CO2. Through the process of photosynthesis, plants convert carbon dioxide (CO2) and sunlight into oxygen (O2) and glucose. Organisms, including the plants themselves, then use that oxygen for respiration, during which they convert the oxygen back into carbon dioxide. The glucose is used for energy. This continuous cycling plays a critical role in life on Earth.

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What is the net ionic equation for the reaction that occurs when aqueous solutions of naoh and hno3 are mixed?

Answers

Answer:-

H+ + OH- --> H2O

Explanation:-

The chemical equation is NaOH + HNO3 --> NaNO3 + H2O

Now for the ionic compounds

HNO3 --> H+ + NO3 -

NaOH--> Na+ + OH-

NaNO3 --> Na+ + NO3-

Water being covalent will remain as H2O,

Hence

HNO3 + NaOH--> NaNO3 + H2O

H+ + NO3 - + Na+ + OH- --> Na+ + No3 - + H2O.

Crossing out common terms

H+ + OH- --> H2O

A compound contains only carbon, hydrogen, and oxygen. Combustion of 139.1 g of the compound yields 208.6 g of CO2 and 56.93 g of H2O. The molar mass of the compound is 176.1 g/mol. *Each part of this problem should be submitted separately to avoid losing your work* 1. Calculate the grams of carbon (C) in 139.1 g of the compound: grams 2. Calculate the grams of hydrogen (H) in 139.1 g of the compound. grams 3. Calculate the grams of oxygen (O) in 139.1 g of the compound. grams

Answers

Answer:

1. Mass of Carbon is 56.89g

2. Mass of Hydrogen is 6.33g

3. Mass of Oxygen is 75.88

Explanation:

The following were obtained from the question.

Mass of the compound = 139.1g

Mass of CO2 produced = 208.6g

Mass of H2O produced = 56.93

1. Determination of mass of Carbon (C). This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C = 12/44 x 208.6

Mass of C = 56.89g

2. Determination of the mass of Hydrogen (H). This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H = 2/18 x 56.93

Mass of H = 6.33g

3. Determination of the mass of oxygen (O).

This is illustrated below:

Mass of the compound = 139.1g

Mass of C = 56.89g

Mass of H = 6.33g

Mass of O = Mass of compound - (mass of C + Mass of H)

Mass of O = 139.1 - (56.89 + 6.33)

Mass of O = 139.1 - 63.22

Mass of O = 75.88

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