Answer:
m_cable = 2,676 kg
Explanation:
For this exercise we must look for the acceleration with the kinematic ce relations
v² = v₀² + 2 a x
since the block starts from rest, its initial velocity is vo = 0
a = v² / 2x
a = 4.2² /(2 2.0)
a = 4.41 m / s²
now we can use Newton's second law
Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.
F = (m + m_cable) a
m_cable = F / a -m
m_cable = 100 / 4.41 - 20
m_cable = 2,676 kg
Unfortunately, the information given does not provide enough data to determine the mass of the steel cable. This is because the force, acceleration, and distance information given only involve the mass of the block, not the cable.
The question is requesting the mass of the steel cable. However, given the information in the question, we don't actually have enough data to determine this. The application of the force, the acceleration of the block, and the distance it covers are all connected through Newton's second law (F = ma) and the equations of motion, but these only involve the mass of the block, not the mass of the cable. Even if we assumed the cable applies the entire 100 N force to the block, this would only allow us to solve for the acceleration of the block, not the mass of the cable. Therefore, the mass of the steel cable cannot be determined with the information provided in the question.
#SPJ12
B. Ultraviolet radiation
C. X-rays
D. Infrared radiation
Answer:
I think D. Infrared radiation.
Answer:
infrared radition
Explanation:
valid
The block's kinetic energy is closest to 1500 Joules.
The energy is always conserved.
So that, the total kinetic energy will be sum of initial potential energy and kinetic energy during falling.
Given that, mass(m)=10kg, v=10m/s, h=10m,g=10m/s^2
K.E=(1/2)mv^2 + mgh
K.E=(1/2)*10*100 + (10*10*10)
K.E=500 + 1000=1500Joule
The block's kinetic energy is closest to 1500 Joules.
Learn more about the kinetic energy here:
Answer:
Kinetic energy = 1500 J
Explanation:
The computation of the block's kinetic energy is shown below:
As we know that
Conservation of energy is
PE_i + KE_i = PE_f + KE_f
where,
Initial Potential energy = PE_i = m gh = 10kg× 10m/s^2 × 10m = 1000 J
Initial Kinetic energy = KE_i = (0.5) m V^2 = (0.5) (10 kg) (10 m/s)^2 = 500 J
Final potential energy = PE_f = mgh = 0
As h = 0 which is at reference line
So
PE_i + KE_i = PE_f + KE_f
Now put these valeus to the above formulas
1000 J + 500 J = 0 + KE_f
After solving this
Kinetic energy = 1500 J
1 pound
1 kilometer
1 gram
Answer:
it's answer is 1 newton
Answer:
603383.67253 m/s
Explanation:
m = Mass of proton =
K = Kinetic energy = 1.9 keV
Velocity of proton is given by
The speed of the protons is 603383.67253 m/s