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Length 21cm area 315cm2 find the breath

Answers

Answer 1

Answer:

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Symbols of:

$\quad\quad\quad\quad\tt{A = A rea}$

$\quad\quad\quad\quad\tt{ l = length}$

$\quad\quad\quad\quad\tt{ b \: = breadth}$

Given that:

$\quad\quad\quad\quad\tt{A = 315 {cm}^(2) }$

$\quad\quad\quad\quad\tt{l = 21cm}$

$\quad\quad\quad\quad\tt{b = \: ? }$

Formula for breadth (b):

$\quad\quad\quad\quad\tt{breadth = (Area)/(length) }$

Solution:

$\quad\quad\quad\quad\tt{b = \frac{315 {cm}^(2) }{21cm} }$

$\quad\quad\quad\tt{\:\:b = {15cm}}$

So, the breadth (b) is:

$\quad\quad\quad\quad\tt \boxed{ \boxed{ \color{magenta}{b = 15cm }}}$

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Answer 2

Answer:

Answer:

Breadth = 15 cm

Step-by-step explanation:

Area = length x breadth

315 = 21 x breadth

$(315)/(21) = (21)/(21) * breadth$ [ dividing both sides by 21 ]

$15 = 1 * breadth\n\nbreadth = 15 \ cm$

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Graph g(x)=-2|x-5|-4

Answers

Answer:

Step-by-step explanation:

Explain why sketching y=sin(x) can help graph y=csc(x)

Answers

The graph of csc x is a parabola with its vertex at the node of the graph of sin x.

y = csc (x) = 1/sin (x)

When you realize that sin (x) is an even function, you can conclude that csc(x) is also even.

Whenyou draw y = sin(x), you will see the zeroes of the function, which are values for which the funcion csc(x) is not defined, but goes to + or - infinity, i.e. you obtain the asymptotes.

You can also realize that the maximums of sin(x) will result in minimums of csc(x).

triangle NOP is similar to triangle QRS. Find the measure of Side SQ. Round your answer to the nearest tenth if necessary

Answers

The measure of side SQ from the given similar triangles is 40.9 units.

What are similar triangles?

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.

Given that, triangle NOP is similar to triangle QRS.

Since the triangles are similar,

NP/SQ = NQ/QR

10/SQ = 13/53.2

13SQ=532

SQ=532/13

SQ=40.9 units

Therefore, the measure of side SQ is 40.9 units.

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brainly.com/question/25882965.

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Answer:

Step-by-step explanation:

the points j(-8,9) and k(-2,-5) are endpoints of a diameter of circle C. What equation would represent circle C

Answers

The equation of circle C will be;

⇒ (x + 5)² + (y - 2)² = 7.61²

What is Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

The points j(-8,9) and k(-2,-5) are endpoints of a diameter of circle C.

Now,

Since, The points j(-8,9) and k(-2,-5) are endpoints of a diameter of circle C.

Hence, The diameter of circle = √(- 2 - (-8))² + (- 5 - 9)²

= √ 6² + 14²

= √36 + 196

= √232

= 15.23

Thus, The radius of circle = 15.23 / 2

= 7.61

And, The center of the circle = (- 8 + (-2)) / 2 , (9 + (-5))/2

= (- 5, 2)

So, The equation circle C is,

⇒ (x - (-5))² + (y - 2)² = 7.61²

⇒ (x + 5)² + (y - 2)² = 7.61²

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Answer:

(x+5)² + (y-2)² =58

Step-by-step explanation:

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