Answer:
I believe it is 1 and 1/6. Dont quote me on it tho. lol
Step-by-step explanation:
Answer:
I think that you should collect the both fracrions
Step-by-step explanation:
The smallest common multiple of 2 and 12 is 12
so:
1*6/2*6+ 8/12= 6/8 + 8/12= 14/12
a) The probability that a new municipal bond issued by a city will receive an A rating is 0.625 or 62.5%.
b) 56% of municipal bonds are issued by cities.
c) The proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.
Let's solve each part of the problem:
a. If a new municipal bond is to be issued by a city, what is the probability that it will receive an A rating?
Use conditional probability here.
Using conditional probability notation, we have:
P(A | City)
To calculate this, use the following formula:
P(A | City) = P(A and City) / P(City)
We are given:
- P(A) = 0.70 (probability of an A rating)
- P(B) = 0.20 (probability of a B rating)
- P(C) = 0.10 (probability of a C rating)
For bonds issued in cities:
- P(City | A) = 0.50 (probability that it's a city if it's rated A)
- P(City | B) = 0.60 (probability that it's a city if it's rated B)
- P(City | C) = 0.90 (probability that it's a city if it's rated C)
Now, let's calculate:
P(A and City) = P(A) * P(City | A)
P(City) = P(A) * P(City | A) + P(B) * P(City | B) + P(C) * P(City | C)
Substitute the values:
P(A and City) = 0.70 * 0.50
= 0.35
P(City) = (0.70 * 0.50) + (0.20 * 0.60) + (0.10 * 0.90)
= 0.35 + 0.12 + 0.09
= 0.56
Now, calculate the conditional probability:
P(A | City) = P(A and City) / P(City)
= 0.35 / 0.56
= 0.625
So, the probability is 0.625 or 62.5%.
b. What proportion of municipal bonds are issued by cities?
56% of municipal bonds are issued by cities.
c. What proportion of municipal bonds are issued by suburbs?
To find the proportion of municipal bonds issued by suburbs, use a similar approach:
P(Suburb) = P(A) * P(Suburb | A) + P(B) * P(Suburb | B) + P(C) * P(Suburb | C)
We are given:
- P(Suburb | A) = 0.40
- P(Suburb | B) = 0.20
- P(Suburb | C) = 0.05
Now, calculate:
P(Suburb) = (0.70 * 0.40) + (0.20 * 0.20) + (0.10 * 0.05)
= 0.28 + 0.04 + 0.005
= 0.325
So, the proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.
Learn more about Probability here:
#SPJ12
The probability that a municipal bond issued by a city will receive an A rating is 35%. The proportion of all municipal bonds issued by cities is 56%. The proportion of all municipal bonds issued by suburbs is 32.5%.
This question requires an understanding of probability and conditional probability.
a) To find the probability that a new municipal bond issued by a city will receive an A rating, we must first determine the likelihood that an A-rated municipal bond is issued by a city. Given that 50% of A-rated bonds are issued by cities and that 70% of all bonds receive an A rating, we can calculate this probability as (0.50)*(0.70) = 0.35, or 35%.
b) To find the proportion of municipal bonds issued by cities, we must add up the bonds issued by cities across all ratings. So, (0.70*0.50) + (0.20*0.60) + (0.10*0.90) = 0.35 + 0.12 + 0.09 = 0.56, or 56%.
c) To calculate the proportion of municipal bonds issued by suburbs, we do the same calculation as in part b) but for suburbs. So, (0.70*0.40) + (0.20*0.20) + (0.10*0.05) = 0.28 + 0.04 + 0.005 = 0.325, or 32.5%.
#SPJ3
Answer:1: 36milimeters 2. 3,6 centimeters 3. 5milimeters 4. .5centimeters 5. 50milimeters 6. 5centimeters
Step-by-step explanation:
Answer:
78.5 in.²
Explanation:
Formula For Area Of Circle: Area = πr²
π: 3.14
r (Half Of Diameter): 5
r²: 25
3.14 · 25 = 78.5
(both questions)
a. What is/are the critical point(s) and domain endpoint(s) where f' is undefined?
b. What is/are the critical point(s) and domain endpoint(s) where f' is 0?
c. From the critical point(s) and domain endpoint(s), what is/are the points corresponding to local maxima?
d. From the critical point(s) and domain endpoint(s), what is/are the points corresponding to local minima?
Answer:
a), b), , c), d)
Step-by-step explanation:
a) Let derive the function:
is undefined when denominator equates to zero. The critical point is:
b) when numerator equates to zero. That is:
This equation shows two critical points:
,
c) The critical points found in point b) and the existence of a discontinuity in point a) lead to the conclusion of the existence local minima and maxima. By plotting the function, it is evident that corresponds to a local maximum. (See Attachment)
d) By plotting the function, it is evident that corresponds to a local minimum. (See Attachment)