MATHEMATICS COLLEGE

What value of y makes the sentence true?y + 3 = 30
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What value of y makes the sentence true? y + - 1

Answers

Answer 1
Answer:

Hey there!

y + 3 = 30

SUBTRACT 3 to BOTH SIDES

y + 3 - 3 = 30 - 3

CANCEL out: 3 - 3 because that gives you 0

KEEP: 30 - 3 because that gives you the value of y

y = 30 - 3

30 - 3 = y

y = 27

Answer: y = 27

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)
Answer 2
Answer: y = 27
Subtract 3 from both sides to get y by itself.

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Answers

Answer:344 i think if im wrong thats alright

Step-by-step explanation:

Helen earns $7.50 an hour at her job, but if she works more than 35 hours in a week, she is paid 1 1/2 times her regular salary for the overtime hours worked. One week her gross pay was $307.50. How many overtime hours did she work that week?

Answers

7.50 * 35 = 262.50

307.50 - 262.50 = $45.00

7.50 * 1.5 = $11.25

45 / 11.25 = 4 OT hours

Mary is having a party at the park. She is going to spend $438.The cost to rent the shelter is $15 plus food is going to cost $6
per person. How many people is she having?

Answers

Answer:

70 people

Step-by-step explanation:

428-15=423

423/6=70.5

she can invite 70 people

A part-time shelf stocker made $8912.03 last year. If she claimed herself asan exemption for $3650 and had a $5700 standard deduction, what was her
taxable income last year?
A. $5262.03
B. $437.97
C. $0
D. $3212.03

Answers

Final answer:

The part-time shelf stocker's taxable income is calculated by subtracting the exemption of $3650 and the standard deduction of $5700 from her annual income of $8912.03, resulting in a negative number, which means her taxable income was $0.

Explanation:

To calculate the taxable income for the part-time shelf stocker who made $8912.03 last year, we need to subtract the exemption and standard deduction from her annual income. The exemption claimed is $3650, and the standard deduction is $5700.

Here's the calculation:

  1. Start with the total annual income: $8912.03.
  2. Subtract the exemption amount: $8912.03 - $3650 = $5262.03.
  3. Subtract the standard deduction: $5262.03 - $5700 = -$437.97.

Since the taxable income cannot be negative, the correct answer is $0. Thus, her taxable income last year was $0.

Learn more about Taxable Income Calculation here:

brainly.com/question/11734493

#SPJ2

Answer: C) $0

Step-by-step explanation:

Demon slayer

Consider the case0502 data from Sleuth3. <<< This is the data. Sleuth3 is preloaded into R studio.Dr Benjamin Spock was tried in Boston for encouraging young men not to register for the draft. It was conjectured that the judge in Spock’s trial did not have appropriate representation of women. The jurors were supposed to be selected by taking a random sample of 30 people (called venires), from which the jurors would be chosen. In the data case0502, the percent of women in 7 judges’ venires are given.

a. Create a boxplot of the percent women for each of the 7 judges. Comment on whether you believe that Spock’s lawyers might have a point.

b. Determine whether there is a significant difference in the percent of women included in the 6 judges’ venires who aren’t Spock’s judge.

c. Determine whether there is a significant difference in the percent of women incuded in Spock’s venires versus the percent included in the other judges’ venires combined. (Your answer to a. should justify doing this.)

Answers

Answer:

Consider the following calculations

Step-by-step explanation:

The complete R snippet is as follows

install.packages("Sleuth3")

library("Sleuth3")

attach(case0502)

data(case0502)

## plot

# plots

boxplot(Percent~ Judge, data=case0502,ylab="Values",

main="Boxplots of the Data",col=c(2:7,8),horizontal=TRUE)

# perform anova analysis

a<- aov(lm(Percent~ Judge,data=case0502))

#summarise the results

summary(a)

### we can use the independent sample t test here

sp<-case0502[which(case0502$Judge=="Spock's"),]

nsp<-case0502[which(case0502$Judge!="Spock's"),]

## perform the test    

t.test(sp$Percent,nsp$Percent)

The results are CHECK THE IMAGE ATTACHED

b)

> summary(a)

Df Sum Sq Mean Sq F value Pr(>F)

Judge 6 1927 321.2 6.718 6.1e-05 *** as the p value is less than 0.05 , hence there is a significant difference in the percent of women included in the 6 judges’ venires who aren’t Spock’s judge

Residuals 39 1864 47.8

---

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

c)

t.test(sp$Percent,nsp$Percent)

  Welch Two Sample t-test

data: sp$Percent and nsp$Percent

t = -7.1597, df = 17.608, p-value = 1.303e-06 ## as the p value is less than 0.05 , hence we reject the null hypothesis in favor of alternate hypothesis and conclude that there is a significant difference in the percent of women incuded in Spock’s venires versus the percent included in the other judges’ venires combined

alternative hypothesis: true difference in means is not equal to 0

95 percent confidence interval:

-19.23999 -10.49935

sample estimates:

mean of x mean of y

14.62222 29.49189

WILL GIVE BRAINLYEST AND 30 POINTS Which of the followeing can be qritten as a fraction of integers? CHECK ALL THAT APPLY 25, square root of 14, -1.25, square root 16, pi, 0.6

Answers

Answer:

25 CAN be written as a fraction.

=> 250/10 = 25

Square root of 14 is 3.74165738677

It is NOT POSSIBLE TO WRITE THIS FULL NUMBER AS A FRACTION,  but if we simplify the decimal like: 3.74, THEN WE CAN WRITE THIS AS A FRACTION

=> 374/100

-1.25 CAN be written as a fraction.

=> -5/4 = -1.25

Square root of 16 CAN also be written as a fraction.

=> sqr root of 16 = 4.

4 can be written as a fraction.

=> 4 = 8/2

Pi = 3.14.........

It is NOT POSSIBLE TO WRITE THE FULL 'PI' AS A FRACTION, but if we simplify 'pi' to just 3.14, THEN WE CAN WRITE IT AS A FRACTION

=> 314/100

.6 CAN be written as a fraction.

=> 6/10 = .6
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