1) Two pieces of a pole arle cut into 5 inches each from an original pole that was 20 incheslong. What is the length of the remaining part of the 20 inch pole?
HELP Please

Answers

Answer 1
Answer:

Answer:

it is 10 because 5x2= 10and20-10=10


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Answers

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

Plzzzz help giving 30 points

Answers

Answer:

why is there only 5 points?

Step-by-step explanation:

What is the circumference of earth's equator?

Answers

Answer:

40,075 kilometers

Step-by-step explanation:

The distance around the Earth at the Equator, its circumference, is 40,075 kilometers

HELP FATS PLEASE
WILL MARK BRAINLEYST
HOW TO STEP BY STEP SOLVE THIS​

Answers

Answer:

Step-by-step explanation:

(y+2)'2-5=20

(y+2)'2=15

y·y+4=15

y·y=11

y=11y

y=5.5

T is the same as the quotient of 175 and p

Answers

Answer:

t=175÷p

Step-by-step explanation:

t is equal to 175 divided by p

John's electricity bill costs $20.90 per month plus $1.23 per kilowatt hour. How many kilowatt hours can he use and keep his monthly cost no more than $109

Answers

Answer:

71.63 kilowatts hours

Step-by-step explanation:

We are told in the question:

John's electricity bill costs $20.90 per month plus $1.23 per kilowatt hour.

We are to find, How many kilowatt hours can he use and keep his monthly cost no more than $109.

Step 1

$109 - $20.90

= $88.1

$88.1 is the amount left to spend on killowatts of electricity per hour after removing the normal monthly electricity bill in a month

Step 2

$1.23 = 1kilowatts per hour

$88.1 = y kilowatts per hour

Cross Multiply

= $1.23 × y kilowatts per hour = $88.1 × 1 kilowatts per hour

y kilowatts per hour = $88.1 × 1 kilowatts per hour/ $1.23

= 71.62601626kilowatts hour.

Approximately = 71.63 kilowatts hour

Therefore, John can use 71.63 kilowatts per hour and keep his monthly cost no more than $109

Answer:

71

kilowatt hours can he use and keep his monthly cost no more than $109