Answer:
140 toy cars
Step-by-step explanation:
The ratio of Ed's toy car to Pete's toy car is initially given as 5:2
Ed gave Pete a total number of 30 cars
Let x represent the greatest common factor that exists between both number
Number of Ed's car is represented as 5x
Number of Pete car is represented as 2x
Since they each have an equal number of cars which is 30 then we can solve for x as follows
5x-30=2x+30
Collect the like terms
5x-2x= 30+30
3x= 60
Divide both sides by the coefficient of x which is 3
3x/3=60/3
x=20
Ed's car is 5x, we substitute 20 for x
5(20)
= 100 cars
Pete car is 2x,we substitute 20 for x
2(20)
= 40 cars
Therefore, the total number of cars can be calculated as follows
= 100+40
= 140 toy cars
Hence they have 140 toy cars altogether
Answer:
140
Step-by-step explanation:
The graph of linear inequality (2y > x – 2) can be drawn by determining the x-intercept and y-intercept of the equation (2y = x - 2).
Given :
Inequality -- 2y > x – 2
The graph of the inequality can be drawn by using the following steps:
Step 1 - First find the y-intercept by putting (x = 0) in equatiuon (2y = x – 2).
y = -1
Step 2 - Now, find x-intercept by putting (y = 0) in equatiuon (2y = x – 2).
x = 2
Step 3 - Now, draw the line that passes through (0,-1) and (2,0).
Step 4 - Now, shade the upper part of the line, the resulting graph is the graph of (2y > x – 2).
Therefore, the correct option is C).
For more information, refer to the link given below:
The answer is 3C. Rate 5 stars
A.
9
B.
3
C.
–3
D.
–9
Answer:
$1,199 per year.
Step-by-step explanation:
Tina Cole is a certified financial adviser.
She purchased equipment for her office costs = $8,843
After 7 years of use the trade-in value of the equipment is estimated = $450
Total depreciation in 7 years = 8,843 - 450 = $8,393
We have to calculate the annual depreciation using the straight-line method.
So we divide $8,393 by 7
$8,393 ÷ 7 = $1,199
The annual depreciation of the equipment is $1,199 per year.
B. 12x⁵
C. 12x⁶
D. 4x⁵
E. 4x⁶
Can someone explain this one for me?