MATHEMATICS HIGH SCHOOL

A square pyramid is shown. What is the surface area? A square based pyramid, with bases labeled 3.5 centimeters and side length of triangle labeled 7 centimeters.

19.25 cm2
30.625 cm2
49.625 cm2
61.25 cm2

Answers

Answer 1
Answer: Given:
square based pyramid = 3.5 cm base
side length = 7 cm

Base Area = (3.5cm)² = 12.25cm²

Surface Area = Base Area + 2sl = 12.25cm² + (2 * 3.5cm* 7cm)
S.A = 12.25 cm² + 49 cm²
S.A = 61.25 cm²  
Answer 2
Answer:

Answer:

61.25 thank you next

Step-by-step explanation:

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Two of the three sides of a triangle are 20 and 15. Which of the following numbers is not a possible perimeter of the triangle?a. 52b. 57c. 62d. 67 e.72
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The perimeter of a rectangular room is 32m.The length of a diagonal is 8m more than than the width.Find the dimensions of the room.

Answers

Answer: 12m by 4m.

Step-by-step explanation: You are looking for the dimensions of the room here, also known as the length and width.

Let’s make width equal to x since we don’t know what the value is. Length is going to be x + 8 since the diagonal is 8m MORE than the width.

w = x

l = x + 8

Use the equation for the perimeter.

P = 2l + 2w

Plug in your values:

32 = 2(x + 8) + 2(x)

Now, solve for x! First start by distributing the 2:

32 = 2x + 16 + 2x

Next, add like terms:

32 = 4x + 16

Subtract 16 from both sides:

16 = 4x

Divide by 4 on both sides:

4 = x

Now we have x, but remember, x is equal to the width. We just solved for width so now we need length.

l = x + 8

Plug in your x and solve:

l = 4 + 8

l = 12

Your length is 12m and your width is 4m, therefore, the dimensions of the rectangular room are 12m by 4m.

Please help 6n^2-5n^2-7n^2 simplify the expression

Answers

Since 6n^2 and −5n^2 are like terms then add −5n^2 to 6n^2 to get n^2.

n^2−7n^2

Since n^2 and −7n^2 are like terms then add −7n^2 to n^2 to get −6n^2.

The answer is −6n^2



In the circle, measure of Arc BC = 62°. The diagram isn't drawn to scale. what is the measure of Arc BCP?

Answers

Answer:

Option D. ∠BCP = 31°

Step-by-step explanation:

As we know by the theorem tangent and chords, an angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc.

Theorem clearly reveals ∠BCP = (mBP)/(2)

Since arc BC = 62°

So ∠BCP = (62)/(2)=31

Option D. ∠ BCP = 31° is the answer.
PQ is the tangent, therefore you can use a theorem: The arc measure is double the amount of the angle the tangent makes.

So: 62/2=31

If a square has an area of 225 square feet what is the length of each side

Answers

The area of the square: A=a^2

where "a" is a length of side.


Therefore:
A=225\ ft^2\ and\ A=a^2\Rightarrow a^2=225\Rightarrow a=√(225)\Rightarrow \boxed{a=15\ (ft)}

Let f(x) = -5x - 4 and g(x) = 6x - 7. Find f(x) + g(x)

Answers

f(x) + g(x)
(-5x - 4) + (6x - 7)
Combine similar terms:
(6x - 5x) + (-4 + -7)
x + (-11) or x - 11


Brainiest would be nice.

7. PQ contains points Rand S such that PR, RS and SQ are respectively three consecutive evenintegers. If PQ is 54, find the length of the middle segment, RS

Answers

The length of the middle segment RS is determined as 18.

How to calculate the middle segment?

Let's assume that the three consecutive even integers are x, x + 2, and x + 4

So, the length of PR (x) + the length of RS (x + 2) + the length of SQ (x + 4) equals the total length of PQ (54).

Mathematically, this can be represented as:

x + (x + 2) + (x + 4) = 54

Now, let's solve for x:

3x + 6 = 54

Subtract 6 from both sides:

73x = 48

Now, divide by 3:

x = 16

So, the first even integer (PR) is 16, the second even integer (RS) is 16 + 2 = 18, and the third even integer (SQ) is 16 + 4 = 20.

Thus, the length of the middle segment RS is 18.

Learn more about middle segment here: brainly.com/question/26166058

#SPJ3

Answer:

RS = 18

Step-by-step

PR = x

RS = x+2

SQ = x+4

x+(x+2)+(x+4)=54

3x+6=54

3x=48

x=16

PR = 16

RS = 18

SQ = 20
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