What is the answer for 3{5[10+5(500-100)+399]}

Answers

Answer 1
Answer: Okay. Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. Next, Handle 5(400). That brings you to 3{5{10+2,000+399]}. Then handle all the addition. That leads to 3[5(2,409)]. Next, configure 5(2409). That leads to 3(12045). Then do that one which ends as 36,135 for a final answer.
Answer 2
Answer: Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. then Handle 5(400). That brings you to 3{5{10+2,000+399]}. next handle all the addition. That brings you to 3[5(2,409)]. Next, configure 5(2409). That gives you 3(12045). Then do that one which ends as 36,135 for a final answer.qx

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A square quilt for a child’s bed has a border made up of 44 pieces with an area of x each, and 4 small squares with an area of 1 square inch each. The main part of the quilt is made of 121 squares with an area of x 2 each. Find an expression for the area of the quilt.

Answers

Answer:

A = ( 11x + 2 )²

Step-by-step explanation:

To find the total area of the quilt, we need to add up all the areas given:

If the border has 44 pieces with an area of x each one, that area is 44x.

The area of 4 squares of 1 in² each is 4×1 in² = 4 in².

The main part is made up of 121 squares with an area of x², which is 121x².

Adding those areas up, we get the expression for the total area:

A = 121x² + 44x + 4

You can easily notice that 121 = 11² and 4 = 2². If you double its product (2·11·2) = 44

So:

A = ( 11x + 2 )²

Solve for x algebraically: 7-3(4x-8)<6x+12-9x

Answers

7-3(4x-8)<6x+12-9x
7-12x+24<6x+12-9x
-12x-6x+9x<12-7-24
-9x<-19
-x<-19/9
x>19/9

Answer: x>19/9          or          (19/9 , +∞)

Prove that, if:y=\frac { { x }^( n+1 ) }{ n+1 } +C

Then:

\n \n \frac { dy }{ dx } ={ x }^( n )

By differentiating...

Answers

y=(x^(n+1))/(n+1)+C\n\ny'=\left((x^(n+1))/(n+1)+C\right)'\ny'=\left((x^(n+1))/(n+1)\right)'+C'\ny'=(1)/(n+1)\cdot (x^(n+1))'+0\ny'=(1)/(n+1)\cdot (n+1)x^n\ny'=x^n

Xian and his cousin Kai both collect stamps, and Kai has 68 stamps. The boys recently joined different stamp collecting clubs. Xian’s club sill send him 12 new stamps per month. Kai’s club will send him 8 new stamps per month. After how many months will Xian and Kai have the same number of stamps? How many stamps will each have?

Answers

Assuming that Xian starts with 0 stamps, you set the equations equal to each other to find what month they have the same amount of stamps.

(68 from Kai's original stamps) (8 from how many per month)
(0 from Xian's original stamps) (12 from how many per month)
68+8m=0+12m
solve for m in this equation and you get 68=4m
and 68/4 = 17 months

For how many stamps each will have, you plug in 17 into m in Xian's equation (you could do either but Xian's is easier):
0+12m
0+12(17)=204
204 stamps.

Hope this helped, it was kinda long lol

toothbrush 95g toiletries 1.4kg shoes 3 1/8 kg beach towel 0.6kg clothes 8580g what's the total weight

Answers

toothbrush = 95g
toiletries = 1.4kg
shoes = 3 1/8 kg
beach towel = 0.6 kg
clothes = 8580 g

2 units are present, grams and kilograms, we need to convert one of these units into the other.

since majority of the items are in kg, we convert the g to kg.

1 kg = 1000 g

toothbrush: 95g * 1kg/1000g = 95kg/1000 = 0.095 kg
clothes: 8580g * 1kg/1000g = 8580kg/1000 = 8.58 kg
shoes 3 1/8 kg = 3.125kg
 
toothbrush:        0.095 kg
toiletries             1.400 kg
shoes                 3.125 kg
beach towel       0.600 kg
clothes               8.580 kg
total weight      13.800 kg

   

Answer:

Step-by-step explanation:

Hi sorry for bathed the you do you no the answer please

Jayden’s new puppy weighed 11 and one fourth pounds at 4 weeks old. At four weeks, the puppy weighed three fifths times as much as at 16 weeks. Which equation can be used to find how much Jayden’s puppy weighs at 16 weeks old

Answers

Step-by-step explanation:

Weight of the puppy at 4 weeks old:

\large{11 (1)/(4) } pounds = \large{ (45)/(4) } pounds

This weight is 3/5th times of the weight of puppy in 16 weeks. Let's assume the weight of puppy in 16 weeks be x. Then, 3/5th of x is 45/4 pounds.

Inequationform,

\boxed{ \large{(3)/(5) x = (45)/(4) }}

Multiplying 5/3 both sides to isolate x on LHS,

\large{x = (45)/(4) * (5)/(3) }

\large{x = (75)/(4) = 18.75} pounds

The equation used for finding the weight of puppy is 3x/5 = 45/4. And Jayden's puppy weighed 18.75 pounds in 16 weeks.