Jen's pace is approximately 13 minutes per mile.
To calculate Jen's pace, we need to determine the time it took her to run 1 mile.
Jen ran 9 miles in 117 minutes, so we divide the total time by the number of miles:
Pace = Total time / Number of miles
Pace = 117 minutes / 9 miles
To simplify the pace, we can convert 117 minutes into hours by dividing it by 60:
Pace = (117 minutes / 60) hours / 9 miles
Pace ≈ 1.95 hours / 9 miles
Now, to find the pace in minutes per mile, we can convert 1.95 hours to minutes by multiplying it by 60:
Pace ≈ (1.95 hours × 60) minutes / 9 miles
Pace ≈ 117 minutes / 9 miles
Therefore, Jen's pace is approximately 13 minutes per mile.
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Answer:1/6
Step-by-step explanation:
The required distance after time t is given as 1.5t.
Given that,
Speed in the race is given as 1.5 meters per second, to determine distance, d, is covered after, t, seconds.
Distance is defined as the object traveling at a particular speed in time from one point to another.
Speed is defined as when an object is subjected to movement, the distance covered by the object in a certain time interval is the speed of that object.
Here,
Speed = 1.5 m/s
Distance = speed × time
Distance = 1.5 × t
Distance(d) = 1.5t
Thus, the required distance after time t is given as 1.5t.
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cos(135)
and then take the reciprocal
Angle ADB is 3 times larger than angle BDC. By assigning a variable to BDC, an equation can be formed to find the values of both angles. BDC is 45 degrees and ADB is 135 degrees.
The given problem states that angle ADB is 3 times larger than angle BDC. Let's assign a variable to angle BDC, such as x degrees. Since angle ADB is 3 times larger, it would be 3x degrees. The sum of angle ADB and angle BDC is equal to 180 degrees, as they form a straight line.
Therefore, we can write the equation 3x + x = 180 to represent the sum of the angles.
Simplifying the equation, we get 4x = 180. Dividing both sides by 4, we find that x = 45 degrees. Hence, angle BDC is 45 degrees and angle ADB is 3 times larger, resulting in 3 * 45 = 135 degrees.
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