How does the amount, or magnitude, of charge on an object affect its attraction or repulsion of another object?

Answers

Answer 1

Answer: The greater the magnitude of the charge on an object, the greater the force of attraction or repulsion exerted by that object on another.

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Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls through a distance during a time 2t. If air resistance is negligible, what is the relationship between A and B?

Answers

Answer:

Distance covered by B is 4 times distance covered by A

Explanation:

For an object in free fall starting from rest, the distance covered by the object in a time t is

$s=(1)/(2)gt^2$

where

s is the distance covered

g is the acceleration due to gravity

t is the time elapsed

In this problem:

- Object A falls through a distance $s_A$ during a time t, so the distance covered by object A is

$s_A=(1)/(2)gt^2$

- Object B falls through a distance $s_B$ during a time 2t, so the distance covered by object B is

$s_B=(1)/(2)g(2t)^2 = 4((1)/(2)gt^2)=4s_A$

So, the distance covered by object B is 4 times the distance covered by object A.

What is the formula for calculating density?A. density=mass/volume
B. density=mass*volume
C. density=volume/mass
D. density=mass + volume

Answers

Density can be determined by themass of an object and how much it takes up space (volume). It is represented bythe formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the massin kg or lb and V is the volume in m^3 or ft^3. The answer would be A. For example, you are given the mass of anobject of 40.5kg and a volume of 15m^3. Find its density.

D = M/V
D = (40.5 kg)/ (15 m^3)
D = 27/10 or2.7 kg/m^3

Answer:

My answer is A.

Explanation:

by using a density triangle, you would have to cover up the density and then it will show you, m over v. so that means you would have to divide.

Air pressure is gravity pulling down on air molecules.
a. True
b. False

Answers

Air pressure is gravity pulling down on air molecules. Like us,air has also mass and the pressure is brought down by the earth’s gravitycausing an increase in weight exerted on you as you descend lower into theatmosphere. So, as you enter into the other layers of atmosphere above the troposphere,the air pressure starts to decrease. Below the atmosphere is the hydrosphere. This iswhere all liquid forms are located. And since the seawater has a greater massthan air, it has the greatest pressure. The answer is true.

Answer:

true

Explanation:

The phase of matter which is exposed to normal atmospheric pressure is solely dependent upon temperature? true or false

Answers

The statement above is true. The phase of matter which is exposed to normal atmospheric pressure is indeed solely dependent upon temperature. If the matter is exposed to the normal atm pressure, its temperature depends on it.

Which one of the following is true a. momentum results in a change of force
B. a force results in a change of momentum

Answers

Answer:

Explanation:

You need a specific force to change the momentum of something.

Hope this helps!

When an object is seen moving in relation to a stationary object, the stationary object is called the frame of reference or reference point. Please select the best answer from the choices provided T F

Answers

From the choices provided, the better answer is ' T ', being the
one-letter acronym for the words "true", "truth", and "trust".

This choice is the preferred one, because the statement that
precedes it, dealing with relative motion, is a factually correct
statement.

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Which of the following is a characteristic of elements A. They are always metalsB. They cannot be divided into simpler substances C. They break down when reacting with acids D. They can be altered with and electric current