HCl is the most polar bond, as greater the difference in electronegativity, the more polar the bond. Here, Chlorine is more electronegative than Hydrogen, Bromine, and Iodine, making the HCl bond most polar.
The most polar bond in the list provided is HCl. Polarity in bonds is determined by the difference in electronegativity between the two atoms in the bond. The greater the electronegativity difference, the more polar the bond. Chlorine (Cl) is more electronegative than Hydrogen (H), Bromine (Br), and Iodine (I), and so the bond between Cl and H is the most polar. The other three options (Cl2, HBr, HI) are either bonds between atoms of the same element (and therefore nonpolar because the electrons are shared equally) or are less polar due to the lower electronegativity difference.
#SPJ3
(2) 24 g (4) 4 g
A saturated solution is a solution that can not dissolve any more solute in it. The amount of potassium nitrate that can be dissolved to make a saturated solution is 29 gm.
The capability of the solute to get dissolved in the solvent to form a saturated solution is called solubility.
The solubility of potassium nitrate in 100 gm of water at 40 degrees celsius is 64 gm. Hence, 64 gm of potassium nitrate is required in 100 gm of water to form a saturated solution.
In the question, the amount of potassium nitrate in 100gm water is 35 gm so, the amount of the potassium nitrate required more will be,
Therefore, option (1) 29 gm of potassium nitrate should be added more.
Learn more about solubility here:
The solubility of at 40 C is around 64 g in 100 g water ot 0.64 g KNO3 in 100 g water.
Therefore 64 g KNO3 in 100 g water is required for satured solution.
According to the problem there are 35 grams of KNO3 dissolved in 100 grams water
So we need 64 g-35 g= 29 g more KNO3
Hence the correct answer is 1
Solubility:
When the maximum amount of solute is dissolve in the solvent is called solubility. On the basic of solubility the solution are following types:
Saturate solution:
A solution which contains the maximum amount of dissolved solute at the equilibrium is called saturated solution.
Un-saturate solution:
A solution which contains lesser amount of solute as compare to saturated solution. It will be able to dissolver more solute.
Super -Saturate solution:
A solution which contains the more dissolved amount of solute as compare to saturated solution.
Answer:
Explanation:
I took the quiz
Answer: 1.848 g
Explanation: To calculate the moles, we use the equation:
....(1)
For ammonia:
Putting values in above equation, we get:
For the reaction:
By Stoichiometry of the reaction,
4 moles of ammonia combine with 3 moles of Oxygen
Thus 0.132 moles of ammonia will combine with= of oxygen
Thus ammonia is the limiting reagent as it limits the formation of product.
4 moles of ammonia produces 2 moles of nitrogen
0.132 moles of ammonia will produce= of nitrogen
Molar mass of nitrogen = 28 g/mol
Amount of nitrogen produced=
In the given chemical reaction, 8.00 x 10²² molecules of ammonia would produce 37.3 grams of nitrogen gas.
In this chemical reaction, every 4 molecules of ammonia (NH₃) produce 2 molecules of nitrogen gas (N₂). Given you have 8.00 x 10²² molecules of ammonia, this would produce (8.00 x 10²² / 2) x 2 = 8.00 x 10²² molecules of nitrogen gas, according to the reaction stoichiometry.
One molecule of nitrogen gas (N₂) has a molar mass of 28 g/mol. To convert molecules to moles, we need Avogadro's number (6.022 x 10²³ molecules = 1 mol). So, the number of moles of nitrogen gas is (8.00 x 10²² molecules / 6.022 x 10²³ molecules/mol) = 1.33 mole.
Now, by using the molar mass of nitrogen gas, we can find the mass. So, the mass of nitrogen gas = molar mass x moles = 28 g/mol x 1.33 mol = 37.3 grams.
#SPJ6
The mass in grams of one molecule of cholesterol, C27H46O is6.43×10⁻²² g
6.02×10²³ molecules = 1 mole of Cholesterol
But,
1 mole of Cholesterol = 387 g
Thus,
6.02×10²³ molecules = 387 g mole of Cholesterol
6.02×10²³ molecules = 387 g mole of Cholesterol
1 molecule = 387 / 6.02×10²³
1 molecule = 6.43×10⁻²² g of Cholesterol
Thus, the mass of 1 molecule of cholesterol is 6.43×10⁻²² g
Learn more about Avogadro's number:
#SPJ2
The molar mass of cholesterol = 386.654 g/mol = 387 g/mole
3.2 mg cholesterol x 1 g/1000 mg x 1 mole/387 g x 6.02x1023 molecules/mole = 5.0x1018 molecules.
Thus the above approach is appropriate.
Learn more about combustion here: