Explanation:
Sodium has atomic number of 11 with electronic configuration of :
Sodium loose it single electron to attain stability of noble gas configuration. While this process electron gets removed from the outer shell of the sodium atom and it gains positive charge of +1.
(Ionization)
Answer: Option (a) is the correct answer.
Explanation:
Conservation efforts means to carefully preserve or protect something. These efforts are fruitful when a majority of people or communities come together in order to preserve something good for the betterment of environment.
As when maximum number of people come lend their hands for help only then conservation efforts can be achieved.
For example, a city with maximum pollution can only be conserved when maximum groups of people decide to conserve plants or plant more number of trees.
Thus, we can conclude that conservation efforts are most effective when conservation efforts are most effective when multiple groups cooperate.
b. ionic bond
c. polar covalent bond
d. pure covalent bond
e. metallic bond
150 J
B.
270 J
C.
1350 J
D.
2250 J
The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.
W = Fd
W = (450N) (3m)
W = 1350J
The answer is letter C.
Answer:the correct options are A (H⁺(aq)) and E (Mg₃(PO₄)₂(s)).
Explanation:To determine which substances are present in the net ionic equation for the reaction between MgCl2(aq) and H3PO4(aq), we first need to write the balanced molecular equation and then separate it into ions to identify the spectator ions. Spectator ions are those ions that do not participate in the chemical reaction and remain unchanged.
First, let's write the balanced molecular equation:
MgCl2(aq) + 2H3PO4(aq) -> Mg3(PO4)2(s) + 6HCl(aq)
Now, let's break down the equation into ions:
Mg²⁺(aq) + 2Cl⁻(aq) + 2H₃PO₄(aq) -> Mg₃(PO₄)₂(s) + 6H⁺(aq) + 6Cl⁻(aq)
Now, let's identify the spectator ions, which are the ions that appear on both sides of the equation and do not change:
- Mg²⁺(aq) is present on both sides.
- Cl⁻(aq) is present on both sides.
So, the spectator ions are Mg²⁺(aq) and Cl⁻(aq).
Now, let's determine the substances that are part of the net ionic equation, excluding the spectator ions:
Net Ionic Equation: 2H₃PO₄(aq) -> Mg₃(PO₄)₂(s) + 6H⁺(aq)
From the net ionic equation, the following substances are present:
A. H⁺(aq)
E. Mg₃(PO₄)₂(s)
So, the correct options are A (H⁺(aq)) and E (Mg₃(PO₄)₂(s)).
The other ions and compounds do not participate directly in the net ionic reaction and are spectator ions.