Which statement is true? Select one: a. Hydroelectric power, a nonrenewable resource, is generated from moving water. b. Oil, a nonrenewable resource, is processed to make jet fuel. c. Propane, a renewable resource, is used in some heating systems. d. The energy from the sun, a nonrenewable resource, can be converted to electricity in solar cells.

Answers

Answer 1
Answer:

a) False.

Hydroelectric power is arenewable source of energy generated from moving water

b) True.

Oil is a non-renewable source used to make jet fuel

c) False

Propane is a byproduct of natural gas which is a non-renewable source of energy

d) False

Energy from the sun is a renewable source of energy

Ans : b) True

Answer 2
Answer:

Answer:

B

Explanation:


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Which of the following would be the best name for MgCl2? magnesium chlorine magnesium chloride magnesium dichloride monomagnesium dichloride

Answers

Answer:  magnesium chloride

Explanation: Magnesium chloride is an ionic compound which is formed by combination of Mg^(2+) and Cl^- ions.

The name of the ionic compound is written as follows:

The name of the metal is written first followed by the name of the non metal without any prefix but the name of the non metal ends with ide, ite, ate or ite.

Thus the name of MgCl_2 is magnesium chloride.


It would be magnesium chloride.

Chlorine is a wrong name for Cl.

Dichloride doesn't work, even though Cl2 is 2 chloride, but according to some laws of nomenclature, saying dichloride isn't necessary so we don't say it.

And monomagnesium isn't right for the same reason as above.

How does the work needed to lift an object and the gravitational potential energy of the object compare? OThey are equal. OThe work is greater. OThe work is less. OThe comparison dependş on the height.○ they are equal
○ the work is greater
○ the work is less
○ the comparison depends on the height​

Answers

Answer:

They are equal

Explanation:

took the test

Answer:

ITS A JUST FINISHED

Explanation:

SELECT ALL THAT APPLYat STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)
1. Will contain the same number of molecules
2. Will contain the same number of atoms
3. Will occupy the same volume
4. Will have the same g.f.w

Answers

at STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)

The answers are:
1. Will contain the same number of molecules 
3. Will occupy the same volume

Answer: The correct answer is Option 1 and Option 3.

Explanation:

We are given:

0.25 moles of CO_2,H_2\text{ and }NH_3

STP conditions states that 1 mole of a gas occupies 22.4 L of volume.

The volume occupied by all the gases at STP will be 0.25* 22.4=5.6L

According to mole concept: 1 mole of a compound contains 6.022* 10^(23) number of molecules or 1 mole of an element contains 6.022* 10^(23) number of atoms.

We know that the given gases are compounds. Thus, all the three gases will have 0.25* 6.022* 10^(23)=1.5055* 10^(23) number of molecules.

Hence, the correct answer is Option 1 and Option 3.

Glycerol is a syrupy liquid often used in cosmetics and soaps. A 3.25-L sample of pure glycerol has a mass of 4.10 X 10^3 g. What is the density of glycerol in g/cm^3?

Answers

Answer: The density of glycerol will be 1.26cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=(mass)/(Volume)

Given : Mass of glycerol= 4.10* 10^3 g

Volume of bromine =  3.25 L= 3250cm^3  (1L=1000cm^3)

Putting in the values we get:

Density=(4.10* 10^3g)/(3250cm^3)=1.26g/cm^3

Thus density of glycerol will be 1.26cm^3

The density of glycerol used in cosmetics and soaps is 1.26 g/cm³.

FURTHER EXPLANATION

Density is the measure of the compactness of a material. It is the mass per given volume. This can be expressed mathematically as:

Density = (mass)/(volume)  (equation 1)

To solve the problem, we first sort the given in the problem:

mass = 4.10 × 10³ g

volume - 3.25 L

The problem is asking for the density in units of g/cm³ which means that we must first convert the volume from liters to cm³.

volume \ (in \ cm^3) = 3.25 \ L * (1000 \ mL)/(1 \ L) * (1 \ cm^3)/(1 \ mL)\nvolume \ (in \ cm^3) = 3250 \ cm^3

Now we can plug in the values of mass and volume into equation 1:

Density = (4.10 * 10^3 \ g)/(3250 \ cm^3)\n\nDensity = 1.2615 (g)/(cm^3)

Since the given in the problem both have 3 significant figures, the final answer must also have three significant digits only. Therefore,

\boxed {Density = 1.26 (g)/(cm^3)}

The density of glycerol is greater than 1, so when mixed with water it will sink.

LEARN MORE

  1. Learn more about Displacement Method brainly.com/question/11474085
  2. Learn more about Liquid Density brainly.com/question/11301218
  3. Learn more about Dimensional Analysis brainly.com/question/1557970

Keywords: Density, Mass, Volume, Unit Conversion

An aqueous solution has a mass of 490 gramscontaining 8.5 103 gram of calcium ions. The
concentration of calcium ions in this solution is
(1) 4.3 ppm (3) 17 ppm
(2) 8.5 ppm (4) 34 ppm

Answers

One way of expressing concentration is by expressing it by parts per million or ppm. Parts per million is equal to 1 milligram of solute per kilogram of solution. The problem is solved as follows:
ppm = .0085103 mg / .490 kg = 0.017 ppm

write a balanced chemical equation for the reaction of zncl2 with excess NaOH to produce Na2Zn(oh)4 sodium zincate. what mass of sodium zincate can be produced from 2.00 g of ZNCl2 with excess Naoh by this reaction?

Answers

4NaOH _((aq)) + ZnCl_(2)_((aq)) ----\ \textgreater \ Na_(2)Zn(OH)_(4)_((ppt)) + 2NaCl (aq)
 
mol = (mass)/(molar mass)
∴  mol of ZnCl_(2) = (2.00 g)/([(65)+(35.5 * 2)g/mol)
                                    =  (2.00 g)/(136 g/mol)
                                    =  0.0147 mol

Moles of Na_(2)Zn(OH)_(4) :
ratio of ZnCl_(2) : Na_(2)Zn(OH)_(4)
                       1      :       1
Moles of Na_(2)Zn(OH)_(4) <span> = 0.0147 mol

Mass = Molar Mass * Mol
∴ Mass of Na_(2)Zn(OH)_(4) <span> = [(23 * 2)+(65)+(16 * 4) + (1*4)] g/mol * 0.0147 mol
                                                       = 179 g/mol * 0.0147 mol
                                                       = 2.63 g