Answer:
Step-by-step explanation:
The route makes a right triangle with legs 3 mi and 4 mi, and the hypotenuse of x mi.
Use Pythagorean to find the distance:
Vector Review Practice Answers:
1. B - initial (14,-5); terminal (0,0)
2. A - sqrt(22^2 + 4^2)
3. B - <4,12>
4. D - Yes, the two vectors have the same magnitude and direction.
5. D - Vectors u and v are neither because the angle between the two vectors is not equal to 0 degrees, 90 degrees, or 180 degrees
6. C - approximately 4 mi. at a direction angle of 56 degrees northeast
7. A - approximately 174 mph at a direction angle of 58 degrees northeast
8. A - -200
9. D - W = 59 ft*lbs
10. C - u = 4/5i - 3/5j
Answer: 8/3
Step-by-step explanation:
13 through 16
Answer:
13. C
14. B
15. C
16. D
Step-by-step explanation:
Let q represent the number of quarters he has. Then q-9 is the number of dimes, and 3q is the number of nickels. His total change is ...
0.25q + 0.10(q-9) + 0.05(3q) = 7.10
0.50q - 0.90 = 7.10
q = (7.10 +0.90)/0.50 = 16
The carrier has 16 quarters, 7 dimes, and 48 nickels.
asked to write the rule that models it.
Subtract 6 from the x value to get the y value.
Multiply the x value by 1/2 to get the y value.
Multiply the x value by 1/4 to get the y value.
Add 6 to the x value to get the y value.
8
12
12
6
16
10
(look at picture) pls help
Answer: it’s A
Step-by-step explanation:
Answer:
I check the answer was a or Subtract 6 from the x value to get the y value
Answer:
We conclude that the mean is greater than 25.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 25
Sample mean, = 27
Sample size, n = 100
Alpha, α = 0.05
Sample standard deviation, s = 6.5
First, we design the null and the alternate hypothesis
We use One-tailed(right) z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We reject the null hypothesis and accept the alternate hypothesis.
Thus, the mean is greater than 25.
The null hypothesis is the mean is equal to 25 and the alternative is that the mean is greater than 25. Using a one-sample t-test and 0.05 significance level, the calculated statistic results in rejection of the null hypothesis. Thus, there is sufficient evidence to suggest that the mean daily census in pediatrics is greater than 25.
1. The hypotheses for this scenario are that the null hypothesis (H0): the mean daily census in the pediatrics service is equal to 25, and the alternative hypothesis (H1): the mean daily census in the pediatrics service is greater than 25.
2. The appropriate test for this scenario would be a one-sample t-test, given that we have a sample mean, a population mean, a standard deviation, and we're examining a single group of hospitals.
3. The decision rule would be: if the p-value of our t-test is less than the significance level (α=.05), we reject H0 and accept H1.
4. The test statistic is calculated as follows: t = (Sample Mean-Population Mean)/(Sample Standard Deviation/ √number of observations), this would give us (27-25)/(6.5/√100) = 3.08.
5. Since 3.08 is greater than the critical value for a 0.05 significance level, we reject the null hypothesis. Therefore, there is sufficient evidence to conclude that the mean daily census in the pediatrics service is greater than 25.
#SPJ12
-6x + 2y = 2
Answer:
x = 2, y =7
Step-by-step explanation:
4x - 2y = -6
-6x + 2y = 2
Add the equations together
4x - 2y = -6
-6x + 2y = 2
-----------------------
-2x = -4
Divide each side by -2
-2x/-2 = -4/-2
x = 2
now find y
-6x+2y =2
-6(2) +2y =2
-12+2y =2
Add 12 to each side
-12+12+2y = 2+12
2y =14
Divide by 2
2y/2 =14/2
y =7