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√(2) ^( √(7) )use a calculator to find an approximation for each power. give the maximum number of decimal places that your calculator displaysround this value to ,7 decimal places,.
[tex] \sqrt{2} ^{ \sqrt{7} } [/tex]use a calculator to find - 1

Answers

Answer 1
Answer:

We are given the following expression

\sqrt[]{2}^{\sqrt[]{7}}

Here the base is √2 and its power (exponent) is √7

The value of this expression can easily be calculated using any scientific calculator.

The maximum number of decimal places depends upon the type of calculator you use.

\sqrt[]{2}^{\sqrt[]{7}}=2.50164253682

Let us round this value to 7 decimal places.

\sqrt[]{2}^{\sqrt[]{7}}=2.5016425

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Imari spent half her weekly allowance playing mini-golf. To earn more money, her parents let her wash the car for $4. If she ended up with $12 how much is her weekly allowance? (Prove Your Answer)

Answers

Answer:

$16

Step-by-step explanation:

She spends half of her weekly allowance.

She earns $4.

12-4=8.

8 is half of what she originally had. 8 times two is 16, her weekly allowance

Answer:

$16

Step-by-step explanation:

let x=Imari's allowance

12-4=1/2x

1/2x=8

x=16

Rock concert tickets are sold at a ticket counter. Femalesandmalesarriveat times of independent Poisson processes with rates 30 and 20 customers per hour. (a) What is the probability the first three customers are female

Answers

Answer: The probability that the first three customers are female is 0.216

Step-by-step explanation:

The attachment below shows the calculations clearly.

In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experience that 1%, 3%, and 2% of the products made by each machine, respectively, are defective. A finished product is randomly selected and found to be non-defective, what is the probability that it was made by machine B1?

Answers

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = (P(B|A)P(A))/(P(B)) = (P(B|A)P(A))/(P(B|A)P(A) + P(B|a)P(a))

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =(P(N|B1)P(B1))/(P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)) = ((0.297)(0.3))/((0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)) = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

A particle moving along a line has position s(t) = t^4 − 20t^2 m at time t seconds. Determine: (a)- At which times does the particle pass through the origin? (b)- At which times is the particle instantaneously motionless.

Answers

The particle passes through the origin at t = 0 and t = ±√20. The particle is instantaneously motionless at t = 0 and t = ±√10.

(a) To determine the times at which the particle passes through the origin, we need to find when the position function equals zero. So, we set s(t) = 0 and solve for t.
t4 - 20t2 = 0
Factoring out a t2, we get:
t2(t2 - 20) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial position), and t = ±√20 (approximately t = ±4.47).

(b) To determine when the particle is instantaneously motionless, we need to find when the velocity of the particle is equal to zero. The velocity function of the particle is the derivative of the position function. So, we differentiate s(t) with respect to t to find the velocity function.
v(t) = s'(t) = 4t³ -40t
Setting v(t) = 0, we have:
4t³ -40t = 0
Factoring out a 4t, we get:
4t(t² - 10) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial velocity), and t = ±√10 (approximately t = ±3.16).

Learn more about Particle Motion

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Final answer:

The particle passes through the origin at t = 0 and t = √20 seconds. The particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

Explanation:

The position of the particle at time t is given by the equation s(t) = t4 - 20t2. To determine the times when the particle passes through the origin, we set s(t) equal to zero and solve for t. This gives us the quadratic equation t4 - 20t2 = 0, which can be factored as t2(t2 - 20) = 0. The solutions to this equation are t = 0 and t = ±√20. Since t cannot be negative in this scenario, the particle passes through the origin at t = 0 and t = √20 seconds.

To determine the times when the particle is instantaneously motionless, we need to find the times when the velocity of the particle is equal to zero. The velocity of the particle can be found by taking the derivative of the position function with respect to time, v(t) = 4t3 - 40t. Setting this equation equal to zero and solving for t gives us the cubic equation 4t3 - 40t = 0. This equation can be factored as 4t(t2 - 10) = 0. The solutions to this equation are t = 0 and t = ±√10. Therefore, the particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

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A movie theater charges $8 for adults and $4 for children. How much does it cost a party made up of six adults and ten children to attend?

Answers

Answer:

88

Step-by-step explanation:

$8 for adults 6adults is 8x6=48

$4fir children 19 children is 4x10=40

48+40=88

Hope this helps :)
320 dollars
Multiply 8 by 10 and 4 by 10

One package of tile will cover 3 square feet.How many packages will shee need 8,13,15,39​HELP ASAP

Answers

Hey there! :)

Answer:

13 packages.

Step-by-step explanation:

Begin by finding the total area of this composite figure. Separate the figure into separate rectangles. Use the formula A = l × w to calculate the area of each:

Smaller rectangle:

Subtract 7 from 9 to find the width:

9 -7 = 2. Therefore:

2 × 2 = 4 ft².

Larger rectangle:

7 × 5 = 35 ft².

Add up the two areas to find the area of the entire figure:

4 + 35 = 39 ft².

If each package of tile covers 3 ft², simply divide to find the package of tiles needed:

39 / 3 = 13 packages.

Answer:13

Step-by-step explanation:
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