4x<-2 como se desarrolla esta desigualdad

Answers

Answer 1

Answer:

Answer:

x<-0.5

Step-by-step explanation:

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g 125 students at a college were asked whether they had completed their required English 101 course, and 74 students said "yes". Find the best point estimate for the proportion of students at the college who have completed their required English 101 course. Round to four decimal places.

Answers

Answer:

0.592

Step-by-step explanation:

Total Number of Students =125

Out of these, 74 reported that they have completed their required English 101 course.

To find the best point estimate for the proportion of students at the college who have completed their required English 101 course, we divide the number of students who said "yes" by the total number of students.

$\text{Point Estimate }=(74)/(125) \n=0.592$

X-y/2z=3
Solve for x will mark brainliest

Answers

The answer is x = 6z+y

Three Rivers publishes a catalog each year, last year it had 198 pages back and front. Weprint 150 copies. How much does it cost the college if a ream, 500 pages, cost

$7.40 each?

Answers

Answer:

$222

Step-by-step explanation:

We need to find how many ream was used in the printing forts, to determine how much the College spent.

The catalog is 198 pages, back and front, which means, 1 leaf will take 2 pages. Therefore, 99 pages were used in printing 1 copy of the catalog.

No of pages that were used in printing 150 copies = 150*99 = 14,850 pages.

If 500 pages = 1 realm, therefore,

14,850 pages = 14,850/500 = 29.7.

Since, it's a full team that is sold, let's approximate the number of reams bought to be 30 reams.

If 1 ream costs $7.40, therefore,

30 reams = 30*7.40 = $222

Final answer:

To calculate the cost of printing the catalogs, you need to calculate the total number of pages printed, convert that into the number of reams needed, and then multiply by the cost per ream. The total cost comes out to $444.

Explanation:

This problem involves simple multiplication and division to calculate the cost. The catalog has 198 pages and they print 150 copies, so the total number of pages is 198*150=29,700 pages. Every ream has 500 pages so you need 29,700/500=59.4 reams. But, you can't have a part of a ream, so you should round up to 60 reams. Then you multiply the number of reams by the cost per ream: 60 reams*$7.40/ream=$444. Therefore, the cost to the college is $444.

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The function f(x) = 2x2 + 3 represents the rate of a boat traveling with the current in miles per hour. The function g(x) = x + 2 represents the time the boat traveled in hours. Solve (f • g)(2), and interpret the answer.

Answers

$\boxed{(f\cdot g)(2)=44}$

Explanation:

Here we have two functions, namely:

$f(x)=2x^2+3 \n \n \n g(x)=x+2$

So here we need to perform the product of two functions and evaluate this new function for $x=2$ . So:

$f(x)=2x^2+3 \n \n g(x)=x+2 \n \n \n (f\cdot g)(x)=(2x^2+3)(x+2) \n \n (f\cdot g)(2)=(2* 2^2+3)(2+2) \n \n \boxed{(f\cdot g)(2)=44}$

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Answer:

C.(f • g)(2) = 44, the distance in miles the boat traveled

Step-by-step explanation:

133 * what gets you to 432 1/4

Answers

Answer:

3 1/4

Step-by-step explanation:

You can do a equation:

133x=432 1/4

Which would give you 3.25 but in fraction form it is 3 1/4

Hope this helped!

A 0.143-Henry Inductor is connected in series with a variable resistor to a 208-volt 400-cycle source. For what value of capacitance will the current be (a) 1.04 ampere lagging and (b) 1.04 ampere leading?

Answers

Answer:

A.)359.2, B.)2.5 uf

Step-by-step explanation:

E / I = R

208 / 1.04 = 200 ohms

2*pi*f*L = Xl

6.28*400*.143 = 359.2 ohm

1 / (2*pi*f*Xc) = c

1 /(6.28*400*159.2) = 2.5 uf

Final answer:

The question asked for the value of capacitance that causes the current in an AC circuit to lag or lead. This situation occurs at resonance when the reactance of the inductor equals that of the capacitor. The calculation of capacitance utilizes the resonance formula, and both given scenarios (a and b) were calculated using provided circuit properties.

Explanation:

The subject of this question involves the principles of alternating current (AC) circuits which includes concepts of inductance, capacitance, and impedance. Particularly, the question is asking to find the value of the capacitor (capacitance) that will result in a current that is (a) lagging or (b) leading in an AC circuit with a given inductor connected in series with a resistor and a power source.

Resonance in AC circuits

When the reactance of the inductor, L, equals the reactance of the capacitor, C, the circuit attains a state called resonance. At resonance, the total impedance of the circuit is at its minimum, hence, the current is at its maximum. This happens when the current leads or lags the voltage.

Solving the problem

To calculate the capacitance value, we can utilize the formula for resonance which is given by:

f = 1/(2π√(LC))

Solving for C, we get:

C = 1/(4π²f²L)

Substituting the given values (f = 400 Hz, L = 0.143 H) Into the formula, we calculate for C for both (a) and (b) scenarios.

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