Answer:
The width of the deck is 2m .
Step-by-step explanation:
Let the width of the pool be represented by w. As stated in the problem a deck of uniform width is to be built so the total width of the pool and deck will be w+w = 2w.
Now the total dimensions can be taken as
10m+ 2w and 5m + 2w of both the pool and deck.
Area = length * breadth
126m ²= (10m+ 2w) ( 5m + 2w )
126= 50 + 30 w+ 4w²
0= 50 -126+ 30 w+ 4w²
0 = 30 w+ 4w²- 76
Taking 2 as common
0= 2( 15 w+ 2w² - 38)
2w²+ 15 w - 38= 0
The above equation is the quadratic equation and can be solved as follows.
a= 2 , b= 15 and c= -38
b= -b±√b²- 4ac/2a
Putting the values
b= - 15±√15²- 4( 2)(-38)/2(2)
b= - 15± 23/4
b= - 38/4 or 8/4
b= 2 m
The width cannot be negative so we ignore the negative value
The width of the deck is 2m .
The can be checked by putting the value in the original equation.
126m ²= (10m+ 2w) ( 5m + 2w )
126m ²= (10m+ 2(2)) ( 5m + 2(2) )
126m ²= (10m+ 4) ( 5m + 4 )
126m ²= 14*9
126m ²= 126m ²
because 17 is greater than 8. Do you
agree? Explain your reasoning
15.17 is not greater than 15.8. Meredith statement is wrong.
A number system is defined as the representation of numbers by using digits or other symbols in a consistent manner.
We need to compare both the numbers 15.17 and 15.80.
For comparing two number we need to check the integer part and decimal part.
The integer part is same for both the numbers. so let us move towards decimal part. in tenth place 15.17 has 1 and for 15.80 it has 8.
We know that 8 is greater than 1.
Hence 15.8 is greater than 15.17. Merediths answer is wrong.
To learn more on Number system click:
#SPJ2
Answer:
No
Step-by-step explanation:
Because in the number 15.8, it is equal to 15.80. 80 is more than 17.
Answer: see below
Step-by-step explanation:
Presuming you meant this
0< θ < 90 degree; tan (θ) = 7/8 find cos (θ)
Using the identity
1 + tan²θ = sec²θ (where sec θ = 1/cosθ)
cosθ = √{1/(1 + tan²θ)} = √{ 1/(1 + (7/8)²} = √{ 1/(1 + 49/64)}
= √{ 64/113} = 8/√113 <= answer.
A. The mean, because the data distribution is symmetrical
B. The mean, because the data distribution is skewed to the left
C. The median, because the data distribution is skewed to the left
D. The median, because the data distribution is skewed to the right