the answer would be people
The woman with ptosis and her father have the genotype Pp, while her mother has pp. If she marries a man with normal eyelids (pp), there is a 50% chance that their children will inherit the dominant P allele and have ptosis.
The subject here is centered around genetics, specifically, a dominant genetic disorder called ptosis. The woman with ptosis would have a genotype of Pp, because she inherited one ptosis allele (P, for dominant) from her father and one normal allele (p, for recessive) from her mother. Hence, her father's genotype was also Pp, and her mother's was pp.
If the woman marries a man with normal eyelids (genotype pp), each child would have a 0.5 (or 50%) probability of inheriting the dominant P allele from the mother and thus, having ptosis. This is because each child will get a p allele from the father (since he can provide only that), and either a P or p allele from the mother with the probabilities being 50% for each. Hence, for these offspring, their potential genotypes can be Pp (ptosis) or pp (normal).
#SPJ2
was added to 9.9 ml of sterile buffer. After thorough mixing, this
suspension was further diluted by a 1/100 dilution followed by a
1/10 dilution. One-tenth of a ml of this final dilution was plated
on agar plates. After incubation, 52 colonies were present. How
many colony-forming units were present in the total 10 gram sample
of hamburger?
Answer:
5.2 × 10 ⁹ cfus
Explanation:
Using the dilution factors
0.1 ml of the final dilution has 52 colonies
1 ml will have approximately 520 colonies
10 ml of the final sample will have 5200 colonies
at 1 / 100 dilution
1 ml of the sample will have 5200 colonies
100 ml of the sample will have 520000 colonies
1 ml of the 0.1 ml + 9.9 ml has 520000 colonies
10 ml will have 5200000
at the second stage of the dilution
0.1 ml of the slurry had 5200000 colonies
1 ml will have 52000000 colonies
10 ml will have 520000000 colonies
100 ml of the initial sample ( 10 grams + 90 ml ) = 5200000000 colonies =
5.2 × 10 ⁹ cfu
Final answer:
When crossing a heterozygous round, tall F1 pea plant with a homozygous wrinkled, short pea plant, the probability of the offspring being wrinkled and tall is 1/4.
Explanation:
In pea plants, we have two traits where round seed shape (R) is dominant to wrinkled seed shape (r), and tall height (T) is dominant to short height (t). When a homozygous round, tall plant (RRTT) is crossed with a homozygous wrinkled, short plant (rrtt), the resulting F1 generation will all have the genotype RrTt (heterozygous for both traits). If these F1 plants are then crossed back to the wrinkled, short strain (rrtt), we need to look at each trait separately to determine the phenotype ratios.
For the seed shape, the F1 plants (Rr) crossed with the wrinkled, short (rr) can produce offspring with either Rr or rr genotype. Therefore, the probability of having a wrinkled (rr) offspring is 1/2. For height, the F1 plants (Tt) crossed with the wrinkled, short (tt) can also produce offspring with either Tt or tt genotype. The probability of having a tall (Tt) offspring is 1/2 as well. To find the proportion of offspring that are wrinkled and tall, we multiply the probabilities of the independent events: 1/2 (chance of being wrinkled) × 1/2 (chance of being tall) which equals 1/4.
Therefore, the proportion of offspring that will be wrinkled and tall from this cross is 1/4.
The statement that correctly describes the presence of freckles is there are two alleles for freckles, hence option B is correct.
An allele is a variation of the same sequence of nucleotides at the same place on a long DNA molecule, as described in leading textbooks on genetics and evolution.
Small, brownish to reddish dots on your skin are known as freckles. They frequently appear on your face, neck, back, upper chest, hands, and arms, as well as other sun-exposed places. Even though freckles are typically not harmful, it is always a good idea to keep an eye out for any changes.
Therefore, the statement that correctly describes the presence of freckles is there are two alleles for freckles, hence option B is correct.
Learn more about alleles, here:
#SPJ5
Answer:
b
Explanation:
edge2020
Answer:
decomposer
Explanation:
producer-consumer-decomposer
Answer;
There will be formation of products that are (two glucose molecules) simple sugars that joins to make up maltose; and the enzyme would not be affected as one of the property of an enzyme.
Explanation;
Maltase is the enzyme that catalyzes the conversion of maltose to the simple sugars.
Maltose is a disaccharide that is formed by joining two glucose molecules therefore; the action of the enzyme maltase involves breaking it down to form two glucose molecules.
The enzyme is mostly found in plants, bacteria and yeast.