Ms Smith has 28 sixth graders and 35 seventh graders
she wants to break them down into groups with each group having the same number of students from each grade
for this we have to find the highest common factor of 28 and 35 to see by which both 28 and 35 are divisible by
factors of 28 and 35 are as follows
28 - 1,2,4,7,14,28
35 - 1,5,7,35
the highest common factor both numbers is 7
therefore Ms Smith can break them down into 7 groups
each group will have
28 / 7 = 4 sixth graders
35 / 7 = 5 seventh graders
so each group will have 4 sixth graders and 5 seventh graders
so in each group there will be 4 + 5 = 9 students
she will break them down into 7 groups
each group has 9 students
b. 2
c. 3
d. 4
B. angle C=110
C.angle B=110
D.angle A=110
For the quadrilateral ABCD if Angle D=70 then the angle A cannot be equal to 110 if AB II CD .
It is a trapezoid in which the base angles are equal and the left and right side lengths are equal.
In an isoceles trapezoid the angles made by the base are equal. So if AB II CD and the angle D is 70then the angle C will be 70, Angle B will be 180-70=110 and angle A will be 180-110=70.
Hence the correct option for the given question will be option D.
Learn more about isoscelestrapezoid at brainly.com/question/8644421
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