This is the equation for the combustion of propane.C3H8 + 5O2 → 3CO2 + 4H2O + heat

Which are the reactants and the products in this reaction?

A.
The reactants are C3H8 (propane) and H2O (water). The products are O2 (oxygen) and CO2 (carbon dioxide).

B.
The reactants are C3H8 (propane) and O2 ( oxygen). The products are CO2 (carbon dioxide) and H2O (water).

C.
The reactants are CO2 (carbon dioxide) and H2O (water). The products are C3H8 (propane) and O2 ( oxygen).

D.
The reactants are O2 (oxygen) and CO2 (carbon dioxide). The products are C3H8 (propane) and H2O (water).

Answers

Answer 1

Answer:

Answer:

Explanation:

Reactants are the compounds which reaction produce the products. In general terms this can be expressed symbolically as follows:

reactants -> products

Other phenomena like heat are omitted because are not always present, that is, only compounds are included. Therefore, in this reaction the reactants are C3H8 (propane) and O2 ( oxygen) and the products are CO2 (carbon dioxide) and H2O (water)

Answer 2

Answer:

Answer:

$\huge \boxed{\mathrm{Option \ B}}$

$\rule[225]{225}{2}$

Explanation:

$\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O$

Balancing Carbon atoms on the right side,

$\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O$

Balancing Hydrogen atoms on the right side,

$\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O$

Balancing Oxygen atoms on the left side,

$\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O$

The reactants are on the left side of the reaction:

$\sf \boxed{\sf C_3 H_8 +O_2} \Rightarrow CO_2 + H_2 O$

Propane and oxygen are the reactants.

The products are on the right side of the reaction:

$\sf C_3 H_8 +O_2 \Rightarrow \boxed{\sf CO_2 + H_2 O}$

Carbon dioxide and water are the products.

$\rule[225]{225}{2}$

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Which layer of the earth can only be studied by indirect means

Answers

The mantle stretches down 2,890 kilometers, making it the Earth's thickest layer and the core that can be studied only by indirect means.

What are the layers of earth?

The layers of earth can be defined as the layer which is present inside the earth surface.

There are basically three different layers of earth.

Crust - It is defined as the a rocky planet's, dwarf planet's, or natural satellite's outermost solid shell.
Mantle - It is defined as the thick layer of heated, solid rock between the Earth's crust and the molten iron core.
Core - It is defined as the center of gravity where all the movements begins.

Thus, the mantle stretches down 2,890 kilometers, making it the Earth's thickest layer and the core that can be studied only by indirect means.

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Everything except for the crust, including the Mantle and the core.

What is agriculture

Answers

the science or practice of farming, including cultivation of the soil for the growing of crops and the rearing of animals to provide food, wool, and other products.

Answer:

the science or practice of farming, including cultivation of the soil for the growing of crops and the rearing of animals to provide food, wool, and other products.

Paige heated 3.00 g mercury (II) oxide (HgO, 216.59 g/mol) to form mercury (Hg, 200.59 g/mol) and oxygen (O2, 32.00 g/mol). She collected 0.195 g oxygen. What was the percent yield of oxygen?

Answers

the balanced chemical equation for decomposition of HgO is as follows

2HgO --> 2Hg + O₂

stoichiometry of HgO to O₂ is 2:1

number of HgO moles heated are - 3.00 g / 216.59 g/mol = 0.0139 mol

according to stoichiometry of reaction -

number of O₂ moles formed = 0.0139 mol/ 2 = 0.00695 mol

mass of O₂ to be formed - 0.00695 mol x 32.00 g/mol = 0.2224 g

but the actual yield = 0.195 g

percent yield = actual yield / theoretical yield x 100 %

percent yield = 0.195 g / 0.2224 g x 100 % = 87.7 %

answer is 87.7 %

Answer:

The correct answer is 87.8%

What 2 tools do we use to measure volume?

Answers

Answer:

Explanation:

what are the answer choices? there are multiple tooks

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron falls from the n = 7 to the n = 4 principal energy level. Recall that the energy levels of the H atom are given by En = –2.18 × 10–18 J(1/n2)

Answers

Answer:

The wavelength of the light emitted by electron fall will be 216.62 nm.

Explanation:

The change in the energy state of the matter can be obtained from the principal quantum number of the shells.

Energy of 4th shell - Energy of 7th shell = $\rm \Delta$ E

$\Delta$ E = $\rm 2.18\;*\;10^-^1^8\;J\;\left ( (1)/(n_f^2) \;-\;(1)/(n_i^2) \right )$

$\rm \Delta\;E\;=\;-2.18\;*\;10^-^1^8\;\left ((1)/(4^2) \;-\;(1)/(7^2) \right )$

$\rm \Delta\;E\;=\;-2.18\;*\;10^-^1^8\;*\;0.0421$

$\rm \Delta\;E\;=\;0.0917\;*\;10^-^1^8$ J

The wavelength can be calculated as:

$\rm \Delta\;E\;=\;(hc)/(\lambda)$

where, h is Plank's constant,

c is speed of light

$\lambda$ is the wavelength

$\rm 0.0917\;*\;10^-^1^8\;J\;=\;(6.626\;*\;10^-^3^4\;J.s\;*\;2.998\;*\;10^8\;m/s)/(\lambda)$

$\rm\lambda\;=\;216.62nm$ .

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Answer:

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

Explanation:

The energy of nth energy levels of the H atom is given as:

$E_n = -2.18 * 10^(-18) * (1)/(n^2) J$

Energy of the seventh energy level = $E_7$

$E_7=-2.18 * 10^(-18) * (1)/(7^2) J$

$E_7=-2.18 * 10^(-18) * (1)/(7^2) J=-4.4490* 10^(-20) J$

Energy of the seventh energy level = $E_4$

$E_4=-2.18 * 10^(-18) * (1)/(4^2) J$

$E_4=-2.18 * 10^(-18) * (1)/(16) J=-1.3625* 10^(-19) J$

Energy of the light emitted will be equal to the energy difference of the both levels.

$E=E_7-E_4=-4.4490* 10^(-20) J-(-1.3625* 10^(-19) J)$

$E=9.176* 10^(-20) J$

Wavelength corresponding to energy E can be calculated by using Planck's equation:

$E=(hc)/(\lambda )$

$\lambda =(hc)/(E)=(6.626* 10^(-34) Js* 3* 10^8 m/s)/(9.176* 10^(-20) J)=2.166* 10^(-6) m=2166 nm$

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

A solution contains 15 g Na₂CO₃ and 235 g if H₂O? What is the mass% of the solution?

Answers

The total mass of the solution is 15 g (Na₂CO₃) + 235 g (H₂O) = 250 g (solution).

Now, let's calculate the mass percent of Na₂CO₃:
Mass percent of Na₂CO₃ = (mass of Na₂CO₃ / total mass of solution) * 100
= (15 g / 250 g) * 100
= 6%

Therefore, the mass percent of Na₂CO₃ in the solution is 6%.

Final answer:

The mass percent of a solution is calculated by dividing the mass of the solute by the total mass of the solution and multiplying by 100%. In this case, the solute is Na₂CO₃ and the solvent is H₂O. The calculation yields a mass percent of 6% for Na₂CO₃ in the solution.

Explanation:

To calculate the mass percent of a solution, we need the mass of the solute and the mass of the solution (which is the sum of the masses of the solute and the solvent). In your given solution, you have 15 g of Na₂CO₃ (solute) and 235 g of H₂O (solvent). Therefore, the total mass of the solution is 15 g (Na₂CO₃) + 235 g (H₂O) = 250 g.

Now, to find the mass percent of Na₂CO₃ in the solution, we use the following formula:

Mass percent = (mass of solute / total mass of solution) × 100%

Substitute the known values into the formula, we get:

Mass percent = (15 g / 250 g) × 100% = 6%

So, the mass percentage of Na₂CO₃ in the H₂O solution is 6%.

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