One grain of sand weighs 0.0007g. How many grains of sand are in 6300kg. Leave your answer in standard form
Answers
Final answer:
To find out how many grains of sand are in 6300kg, you need to first convert the weight from kg to g and then divide the total weight by the weight of one grain of sand. In this case, the answer is 9 × 10¹³ grains of sand.
Explanation:
To answer your question, we first need to convert the weight from kilograms (kg) to grams (g) since the weight of a grain of sand is given in grams. There are 1,000,000 grams (g) in a kilogram (kg), so 6300kg is equal to 6,300,000,000g (or 6.3 × 10⁹ g in standard form).
Next, we divide the total weight in grams by the weight of a single grain of sand to find the number of grains in the given weight. So, if one grain of sand weighs 0.0007g, we divide the total weight (6.3 × 10⁹ g) by the weight of a single grain of sand to get
9 × 10¹³ grains of sand. This means there are 9 × 10¹³ grains of sand in 6300kg.
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Related Questions
After completing a 10 hour walk, Chester Snowman goes inside to get warm. As he sits by the fire, he starts to melt at a rate of 3 inches per hour. Starting at the height he reached at the end of his walk, determine Chester's height after sitting by the fire for 10 hours.
Matthew's total points that he scored in his basketball season was 200 points. He scored 175 points in the regualr season and the rest were scored during the playoffs. What percent of his total points did he score during his regular season?
Write a function rule for “The output is 9 less than the input.” Let x be the input and let y be the output.
Your teacher is giving you a test worth 100 points containing 40 questions. there are 2 point and 4 point questions on the test. how many of each type of questions are on the test. use a system of linear equations to solve .
Answers
Answer:
Multiples and Submultiples of Volts.
Multiples and submultiples are prefixes and sufixes which are used to express a higher or lower number of a magnitude.
From least to greatest.
Multiples are: deka, hecto, kilo, mega, giga, tera, peta, exa, zetta, yotta.
Submultiples are: deci, centi, mili, micro, nano, pico, femto, atto, zepto, yokto.
Multiples of volts are:
dekavolts:
hectovolts:
kilovolts:
megavolts:
gigavolts:
teravolts:
petavolts:
exavolts:
zettavolts:
yottavolts:
Submultiples of volts are:
decivolts:
centivolts:
milivolts:
microvolts:
nanovolts:
picovolts:
femtovolts:
attovolts:
zeptovolts:
yoktovolts: .
MV =MegaVolt (1 MV = 1000000 V)
KV = KiloVolt (1 KV = 1000 V)
V = Volt (1V = 1 V) :))
mV = miliVolt (1V = 1000 mV)
μV = microVolt (1V) = 1000000 μV
Answers
Answers
Answer: 5.252525...
Step-by-step explanation: Since this decimal does not terminate, it could be an irrational number. However notice that the 25 after the decimal point repeats and remember that repeating decimals are rational numbers.
Therefore, 5.252525... is an example of a rational number.
or
5.4
or
5.48
Any of these is a rational number between 5.2 and 5.5.
have $500 at the end of the year?
A. $507.89
B. $480.40
C. $518.92
D. $492.31
Answers
Final answer:
To have $500 at the end of the year with a 4% APR compounded monthly, you would need to invest approximately $480.40 as a lump sum.
Explanation:
To find the amount of money needed to invest as a lump sum in order to have $500 at the end of the year with an approximate 4% APR compounded monthly, we can use the formula for compound interest:
A = P(1 + r/n)nt
Where:
A = final amount ($500)
P = initial investment (unknown)
r = annual interest rate (4% or 0.04)
n = number of times interest is compounded per year (12)
t = number of years (1)
Plugging the given values into the formula, we can solve for P:
P = A / ((1 + r/n)nt)
P = $500 / ((1 + 0.04/12)12*1)
P ≈ $480.40
Therefore, you would need to invest approximately $480.40 as a lump sum to have $500 at the end of the year.
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Answer: 480.40
Step-by-step explanation:
We can use the formula for compound interest to calculate how much money we will need to invest as a lump sum to have $500 at the end of the year.
FV = PV x (1 + r/n)^(nt)
FV = future value
PV = present value
r = interest rate
n = number of times compounded per year
t = time in years
We know that FV = $500, r = 4% or 0.04, n = 12 (since it is compounded monthly), and t = 1. We can plug in these values to solve for PV.
$500 = PV x (1 + 0.04/12)^(12 x 1)
$500 = PV x (1.003333)^12
$500 = PV x 1.0406
PV = $500 / 1.0406
PV = $480.40
Therefore, we will need to invest $480.40 as a lump sum to have $500 at the end of the year. So, the correct option is B. $480.40.
five thousand eight hundred thirty dollars
five thousand eight hundred fifty-one dollars
six thousand one hundred dollars
Answers
The car costs $4900 before tax.Tax is 6%.$4900 is 100% of the price of the car.Once she adds the 6% tax she will be paying 106% of the price of the car.106% of $4900 =1.06 * $4900 = 5194