• The probability of picking cherry is 5.
• The probability of picking watermelon is 10.
3
What is the probability William will pick a piece of grape gum?
Answer:
37 (i think)
Step-by-step explanation:the probability means the amount of (in this case) the cherry gum or watermelon gum. Add the amount and then subtract the total from the WHOLE number of the WHOLE of the group
(hopefully that made sense)
$27.55
29.95 x 8% (aka .08) = 2.396
29.95- 2.396 = 27.55
Answer:
a) Missing y-values
x = - 2 ==> y = 5
x = - 1 ==> y = 2
x = 1 ==> y = 2
x = 3 ==> y = 10
b) Values of x for y = 4:
x = 1.7 and x = -1.7
Step-by-step explanation:
Given the quadratic function,
y = x² + 1
part a)
to find the y-value for a specific x, just plug in that value of x into the right side and simplify
There are four missing values for
The x values and the corresponding y values are
x = - 2 ==> y = (-2)² + 1 = 4 + 1 = 5
x = - 1 ==> y = (-1)² + 1 = 1 + 1 = 2
x = 1 ==> y = (1)² + 1 = 1 + 1 = 2
x = 3 ==> y = (3)² + 1 = 9 + 1 = 10
part b)
The graph has each unit on the grid for the x-axis = 0.5
and
each unit on the grid for the y-axis = 2
I got this by seeing that between x = 0 and x = 1 there are two units
the value of y at x = -1 or x = 1 is only one vertical unit on the grid and since y = 2 for these values of x, each vertical unit must be 2
Therefore look at the value of y = 4 (which should be two vertical units) on the graph. You can also draw a horizontal line parallel to the x axis at 2 units from the x-axis
It appears that on the positive x-axis for y = 4, x is about halfway between 1.5 and 2 so I would estimate it at 1.75
On the negative x-axis, at y = 4, x is about halfway between -1.5 and -2 so it would be -1.75
One thing to note about quadratic functions is that you get the same value of y for x and -x
So at y = 4, the two possible values of x are
x = 1.75 and x = -1.75
which when using one decimal place will round to 1.7 and 1;75
I am rounding down rather than rounding up since the x value appears be less than 1.75
Mathematically we can solve for x at y = 4 by plugging in values
y = 4 = x² + 1
x² + 1 = 4
x² = 4 - 1 = 3
x =±√3 = ±1.732
which when rounded to 1 decimal place becomes
x = 1.7 and x = -1.7
Answer:
Step-by-step explanation:
a) y = (-2)² + 1 = 5
y = (-1)² + 1 = 2
y = (1)² + 1 = 2
y = (3)² + 1 = 10
b) 4 = x² + 1
x² = 4 - 1 = 3
x = ±√3 = ±1.7
Step-by-step explanation:
Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.
Picture 1 a° = a° they are the same
Picture 2 p= 52° q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.
Picture 3 + 4 Let the obtuse angle MOQ = 2x.
Using the circle theorem, the angle at the centre is twice the angle at the circumference.
Therefore picture 4 tells us and proves;
Angle MNQ = x and angle MPQ = x.
Picture 5
A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.
The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.
Picture 6
The opposite angles in a cyclic quadrilateral add up to 180°.
a + c = 180°
b + d = 180°
Picture 7
Example
Calculate the angles a and b.
The opposite angles in a cyclic quadrilateral add up to 180°.
This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °
So hopefully this will help you remember the format here for quadrilateral shapes within a circle.
b = 180 - 140 = 40°
a = 180 - 60 = 120°