The volume of the original chamber is
V cubic inches. This i
v cubic inches less than the volume of the new
chamber.
Answer:
the original volume is lesser than the new volume by 242.47 in³
Step-by-step explanation:
Volume of a cone is;
V = ⅓πr²h
Where;
r is radius
h is height
For the original chamber;
r = 5.7/2 = 2.85 inches
h = 12 inches
Volume of this original chamber is;
V_orig = ⅓ × π × 2.85² × 12
V_orig = 102.02 in³
In the new design, the chamber is scaled by a factor of 1.5.
Thus;
r_new = 2.85 × 1.5 = 4.275 inches
h_new = 12 × 1.5 = 18 inches
V_new = ⅓ × π × 4.275² × 18
V_new = 344.49 inch³
V_new - V_orig = 344.49 - 102.02 =
Thus, the original volume is lesser than the new volume by 242.47 in³
3m - 14
Ob
3m-4
3m + 16
Od
3m + 3
Answer:
Step-by-step explanation:
This is same as option a.
Answer:
A - 3m-14 is the answer(:
Answer:
You would expect 24 right handed and 6 left handed
Step-by-step explanation:]
5 x 6 =30
prove triangle PAB is an equilateral triangle
HELP PLEASEE
Answer:
If three sides of a triangle are equal and the measure of all three angles is equal to 60 degrees then the triangle is an equilateral triangle. Therefore it is an equilateral triangle.
In ∆PAM and ∆PBM
Hence
∆APB is a equilateral triangle
To solve for x in a triangle with side lengths of 67, 29, and x, we can use the Law of Cosines. The value of x is approximately 47.6.
To solve for x in the given triangle with side lengths 67, 29, and x, we can use the Law of Cosines. The Law of Cosines states that for any triangle with side lengths a, b, and c and angle C opposite side c, the following equation holds true: c^2 = a^2 + b^2 - 2ab*cos(C). In this case, we can substitute the given values into the equation and solve for x. Let's calculate it:
x^2 = 67^2 + 29^2 - 2*67*29*cos(C)
x^2 = 4489 + 841 - 3886cos(C)
Solving for x, we find that x is approximately 47.6.
#SPJ12
Answer:
84°
Step-by-step explanation:
Because every triangle has a combined side length of 180°
67+29=96°
180-96=84°